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4 years ago

Help! locus points!

Mathematics

1 answer:

Liula [17]4 years ago

5 0

Answer:

Circle X with radius 2 cm.
Either of two lines parallel to AB.

Step-by-step explanation:

1. The definition of a circle is all the points in a plane that are at some radius r from a given point (the circle center). That is what you have, with a radius of 2 cm.

2. Parallel lines are the same distance apart everywhere. Each line will have two parallel lines at some given distance from it, one on each side. Here, the separation distance from AB is 1 cm, so your locus of points is the two lines parallel AB that are 1 cm from it on either side.

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X+2y=6 <br> SHOW ALL OF YOUR WORK!

Alika [10]

Answer:

x+2y=6

Subtract 2y from both sides.

x=6−2y

Step-by-step explanation:

x=6-2y

3 0

3 years ago

Read 2 more answers

A 4-column table with 2 rows. Column 1 has entries Sample 1, Sample 2. Column 2 is labeled Apple with entries 40, 43. Column 3 i

Dvinal [7]

Answer:

The answer is A B E

Step-by-step explanation:

8 0

3 years ago

Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )

DedPeter [7]

(a) First find the intersections of $y=e^{2x-x^2}$ and $y=2$ :

$2=e^{2x-x^2}\implies \ln2=2x-x^2\implies x=1\pm\sqrt{1-\ln2}$

So the area of $R$ is given by

$\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx$

If you're not familiar with the error function $\mathrm{erf}(x)$ , then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line $y=1$ with $y=e^{2x-x^2}$ .

$1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2$

So the area of $S$ is given by

$\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx$
$\displaystyle=2\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\mathrm dx$

which is approximately 1.546.

(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve $y=e^{2x-x^2}$ and the line $y=1$ , or $e^{2x-x^2}-1$ . The area of any such circle is $\pi$ times the square of its radius. Since the curve intersects the axis of revolution at $x=0$ and $x=2$ , the volume would be given by

$\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx$

5 0

3 years ago

The scale from a square park to a drawing of the park is 5 miles to 1 miles. The actual park has an area of 1,600 m×2 what is th

Flauer [41]

The user corrected that the scale of a drawing of a park reads: 5 miles to 1 cm , and we know that the park measures 1,600 square meters (user insisted that this measure is given in square meters and not square miles).

So we have to convert the 1600 square meters into miles, knowing that 1 meter is the same as: 0.000621371 miles

then meters square will be equivalents to:

1 m^2 = (0.000621371 mi)^2

then 1600 m^2 = 0.00061776 mi^2

now, since 5 miles are represented by 1 cm, then 25 square miles will be represented by 1 square cm

and therefore 0.00061776 square miles will be the equivalent to:

0.00061776 / 25 cm^2 = 0.000024710 cm^2

So and incredibly small number of square cm.

I still believe that some of the information you gave me are not in meters but in miles. (For example, the park may not be in square meters but in squared miles). The park seems to have the size of a house according to the info.

3 0

1 year ago

I really need help can someone help me with this

TiliK225 [7]

The break-even point is given when:

$C(x)=R(x)$

In another words, when the costs are equal to the revenue. If this happens, the profit will be equal to 0. From the graph, the profit is equal to 0 for 60,000 units.

Answer:

8 0

1 year ago