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Stella [2.4K]
3 years ago
8

Angie and Becky each completed a separate proof to show that the measures of vertical angles AKG and HKB are equal. Who complete

d the proof incorrectly? Explain.
line AB intersecting line GH at K

Angie's Proof


Statement Justification
1. Segment GH intersects segment AB at K 1. Given
2. m∠AKG + m∠GKB = 180°
m∠GKB + m∠HKB = 180° 2. Definition of Supplementary Angles
3. m∠AKG + m∠ GKB = m∠GKB + m∠HKB 3. Substitution Property
4. m∠AKG = m∠HKB 4. Subtraction Property


Becky's Proof

Statement Justification
1. Segment GH intersects segment AB at K 1. Given
2. m∠AKG + m∠GKB = 180°
m∠GKB + m∠HKB = 180° 2. Angle Addition Postulate
3. m∠AKG + m∠ GKB = m∠GKB + m∠HKB 3. Substitution Property
4. m∠AKG = m∠HKB 4. Subtraction Property
Mathematics
1 answer:
BigorU [14]3 years ago
8 0

Linear pair angles, which are angles that together form a straight line are

supplementary angles.

The one that completed the proof incorrectly is <u>Becky</u>.

Reasons:

The two column proof is presented as follows;

Statement {}                                                             Reason

1. Segment GH intersects segment AB at K {}     1. Given

2. m∠AKG + m∠HKB = 180°    {}            2.Definition of Supplementary Angles

m∠GKB + m∠HKB = 180°

3. m∠AKG + m∠HKB = m∠GKB + m∠HKB      {}  3. Substitution property

4. m∠AKG = m∠HKB     {}                                      4. Subtraction Property

The difference between Angie's Proof and Becky's Proof is in Statement 2.

  • Angie states that; m∠AKG + m∠HKB = 180° and m∠GKB + m∠HKB = 180° by definition of Supplementary Angles

  • Becky states that; m∠AKG + m∠HKB = 180° and m∠GKB + m∠HKB = 180° by Angle Addition Postulate

Becky's proof is incorrect because the measure of angles  m∠AKG and

m∠HKB and m∠GKB and m∠HKB are not given, therefore, the use of the

reason of Angle Addition Postulate in statement 2. is incorrect.

Learn more here:

brainly.com/question/13204208

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the surface area of a cuboid is 95cm² and its lateral surface area is 63cm². find the area of its base​
wel

Answer:

The Area of the base is 16 cm² .

Step-by-step explanation:

Given as :

The surface area of the cuboid = x = 95 cm²

The lateral surface area of the cuboid = y = 63 cm²

Let The Area of the base = z cm²

Now, Let The length of cuboid = l cm

The breadth of cuboid = b cm

The height of cuboid = h cm

<u>According to question</u>

∵ The surface area of the cuboid = 2 ×(length × breadth + breadth × height + height × length)

Or, x = 2 ×(l × b + b × h + h × l)

Or, 95 =  2 ×(l × b + b × h + h × l)

Or,  (l × b + b × h + h × l) = \dfrac{95}{2}          ....1

<u>Similarly</u>

∵lateral surface area of the cuboid = 2 ×(breadth × height + length × height)

Or, y = 2 ×(b × h + l × h)

Or, 2 ×(b × h + l × h) = 63

Or, (b × h + l × h) = \dfrac{63}{2}              ......2

Putting value of eq 2 into eq 1

so,  (l × b +  \dfrac{63}{2} ) = \dfrac{95}{2}    

Or, l × b = \dfrac{95}{2} - \dfrac{63}{2}    

Or,  l × b = \dfrac{95 - 63}{2}

i.e l × b = \dfrac{32}{2}

so, l × b = 16

<u>Now, Again</u>

∵The Area of the base = ( length × breadth ) cm²

So, z =  l × b

i.e z = 16 cm²

So, The Area of the base = z = 16 cm²

Hence,The Area of the base is 16 cm² . Answer

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