How are the dividend and divisor of a division expression related to parts of a fraction
1 answer:
You might be interested in
The point (2, 5) is not on the curve; probably you meant to say (2, -5)?
Consider an arbitrary point Q on the curve to the right of P, , where
. The slope of the secant line through P and Q is given by the difference quotient,
where we are allowed to simplify because .
Then the equation of the secant line is
Taking the limit as , we have
so the slope of the line tangent to the curve at P as slope 2.
- - -
We can verify this with differentiation. Taking the derivative, we get
and at , we get a slope of
, as expected.