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Paraphin [41]
3 years ago
6

How are the dividend and divisor of a division expression related to parts of a fraction

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
4 0
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I don’t know what it is :(
WARRIOR [948]
I think it’s 3 for sure
3 0
4 years ago
Read 2 more answers
Create a table and graph y=x+1 demos<br>​
DerKrebs [107]

Answer:

The table will be:

x          y=x+1

1            2

2           3

3           4

4           5

5           6

The graph is shown in figure attached.

Step-by-step explanation:

We need to create table and graph the expression: y=x+1

Table is made, such that we take value of x and find value of y

You can take any values of x from negative values to positive values. I am taking values of x: 1,2,3,4,5 and find value of y.

So our table will be:

x          y=x+1

1            2

2           3

3           4

4           5

5           6

Now, we will plot these value on the graph. x values will be on x-axis and corresponding y-values will be on y-axis.

The graph is shown in figure attached.

8 0
3 years ago
Please help, thanks I’m advance!
netineya [11]

Answer:

A

Step-by-step explanation:

(x+2)©= x©+4x+4

Hsbsbjsjisoajja

3 0
3 years ago
What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

7 0
3 years ago
Glven the line segment RT, with endpolnt R(6,9) and<br> midpoint A(-3,7)
Rzqust [24]
It would be (-12, 5)
7 0
3 years ago
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