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miv72 [106K]
3 years ago
5

The number of decimal places after which the decimal expansion of 23 upon 2²*5 will terminate will

Mathematics
1 answer:
Elenna [48]3 years ago
8 0

Answer:

Given:

⇒ \frac{23}{2^2(5)}

2

2

(5)

23

To Find:

Expansion of the given number = ?

Solution:

⇒ \frac{23}{2^2(5)}

2

2

(5)

23

By opening the squares, we get

⇒ \frac{23}{2\times 2\times 5}

2×2×5

23

⇒ \frac{23}{4\times 5}

4×5

23

⇒ \frac{23}{20}

20

23

⇒ 1.151.15

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Evaluate the following expression. Express your answer in simplest form. 3/16 + 5/8 × 1/2​
miss Akunina [59]

Answer:

1/2

Step-by-step explanation:

We have to follow the order of operations. Since there are no parenthesis or exponents, we do multiplication first. to multiple fractions, we multiply the two numerators (top parts), which in this situation would get us 5*1=5. Then, we multiply the two denominators (bottom parts), which would get us 8*2=16. then we put the first result over the second, and we get 5/16. since the two denominators are the same, we don't need to change anything. we can just add the numerator, and get 8/16, which simplifies to 1/2.

4 0
3 years ago
Javier has a basket of oranges and apples. The number of oranges is 2 more than twice the number of apples in the basket. The di
Vesna [10]
Hello!

Let's put this into a system of equations and have a represent the apples and o represent the oranges.

o=2a+2
0.5o-0.5a=4

Since we can already so what o equals (2a+2) we will substitute it into the second equation and solve for a.

0.5(2a+2)-0.5a=4
1a+1-0.5a=4
1.5a+1=4
1.5a=3
a=2

Now that we know the value of a will put a into the first equation to find o.

o=2(2)+2
o=4+2
o=6

There were 6 oranges and 2 apples.

I hope this helps!
3 0
3 years ago
Simplify. wait for photo
Ksivusya [100]
The ans is3^1/3*9^1/3=27^1/3=3
4 0
3 years ago
A<br> 2x + 5<br> 3x - 2<br> B+<br> X = [? ]
WITCHER [35]

Answer:   7

Step-by-step explanation:

They are alternate interior angle

2x + 5 = 3x -2

2x = 3x -7

-x = -7

x = 7

4 0
3 years ago
* Let S = Span {(2,-1, 1), (3, 1, 1), (1, 2, 0)}. (i) Calculate the dimension of S.
Sholpan [36]

The span of 3 vectors can have dimension at most 3, so 9 is certainly not correct.

Check whether the 3 vectors are linearly independent. If they are not, then there is some choice of scalars c_1,c_2,c_3 (not all zero) such that

c_1 (2,-1,1) + c_2 (3,1,1) + c_3 (1,2,0) = (0,0,0)

which leads to the system of linear equations,

\begin{cases} 2c_1 + 3c_2 + c_3 = 0 \\ -c_1 + c_2 + 2c_3 = 0 \\ c_1 + c_2 = 0 \end{cases}

From the third equation, we have c_1=-c_2, and substituting this into the second equation gives

-c_1 + c_2 + 2c_3 = 2c_2 + 2c_3 = 0 \implies c_2 + c_3 = 0 \implies c_2 = -c_3

and in turn, c_1=c_3. Substituting these into the first equation gives

2c_1 + 3c_2 + c_3 = 2c_3 - 3c_3 + c_3 = 0 \implies 0=0

which tells us that any value of c_3 will work. If c_3 = t, then c_1=t and c_2 = -t. Therefore the 3 vectors are not linearly independent, so their span cannot have dimension 3.

Repeating the calculations above while taking only 2 of the given vectors at a time, we see that they are pairwise linearly independent, so the span of each pair has dimension 2. This means the span of all 3 vectors taken at once must be 2.

3 0
1 year ago
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