Answer:
LHS.= Sin 2x /( 1 + cos2x )
We have , sin 2x = 2 sinx•cosx
And. cos2x = 2cos^2 x - 1
i.e . 1+ cosx 2x = 2cos^2x
Putting the above results in the LHSwe get,
Sin2x/ ( 1+ cos2x ) =2 sinx•cosx/2cos^2x
=sinx / cosx
= Tanx
.•. sin2x/(1 + cos2x)= tanx
Step-by-step explanation:
Answer:
x = -1
Step-by-step explanation:
The easiest way is just to find the antiderivative and graph. The antiderivative is 
. Graphing this with any C shows that 
is the relative minimum.
Answer: y = 6
Step-by-step explanation:
A square's area can be done by using s^2, where s is y in this case. Because there are 5 squares, the area of the figure is 5y^2. Because the area is also 180cm, 5y^2=180.
Then divide both sides of the equation by 5 to get y^2 = 36. Then square root both sides of the equation to get y = 6.
Hope it helps <3
A .
this is false
There’s no answer for x and y
Measure of the angle m ∠ RQS = 58 ° for the given circle with arc RS subtending m ∠RPS=14 x + 46 ° at the center P and m ∠ RQS = 3 x + 43 ° at Q, on the circumference.
As given in the question,
Measure of the angle is given by :
m ∠ RPS=14 x + 46 °
m ∠ RQS=3 x + 43 °
m ∠ RPS = twice m ∠RQS (angle subtended at center of the circle)
14 x +46 =2(3 x + 43)
⇒ 14x + 46 = 6x +86
⇒ 14x-6x=86-46
⇒8x=40
⇒ x=5°
m ∠ RQS = (3 x + 43) °
=[3(5) + 43 ]°
= 58°
Therefore, measure of the angle in the given circle m ∠RQS is equal to the 58 °
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