1427 = (F) (+ F + 60) (2F - 50) (+ 3F)
<em>Each pair of brackets represents one of the classes - F meaning Freshmen Class. It has been split into brackets for demonstrational purposes - nothing is being multiplied.</em>
F is an unknown number and each other class size is based off of that so we put it in algebraic terms in order to work it out.
1 - Freshmen Class
2 - Sophomore Class (Freshmen Class + 60 more students)
3 - Junior Class ( Twice the size of the Freshmen Class - 50 students)
4 - Senior Class (Three times the size of the Freshmen Class)
All this can be simplified to 7F + 10 = 1427
1427 - 10 = 1417
1417/7 = 202.428....
Is there a mistake in the question?
Following the question with 202 as the answer - the number 1424 is reached
If increased to 203 - 1431 is reached.
The answer shouldn't include half a person.
In exponential form: 10^2=3(x+5)
If we were to solve, x=85/3
The estimate would be 1200.
We will set up a proportion for this. 10 out of 60 of the sample were tagged, so that is the first ratio. The 200 that were tagged would be in the numerator of the second ratio (10 was the portion tagged, and 200 is the portion tagged, so they both go on top). We do not know the total number so we use a variable:
10/60 = x/200
Cross multiply:
10*x = 60*200
10x = 12000
Divide both sides by 10:
10x/10 = 12000/10
x = 1200
Answer:
18
Step-by-step explanation:
20/2 + 8
Divide the numerator and denominator by 2
20 / 2
2 / 2
Divide the numbers
10
2 / 2
=
10 / 1
Any expression divided by 1 remains the same
10 + 8 = 18
The equation describes a function whose maximum value is 5. The data set describes a function whose maximum value is also 5. Comparing the maximum values, we must conclude ...
... It is the same for both functions.
_____
Please note that the premise is that g(x) is a quadratic function. It is definitely NOT a quadratic function in the usual sense of the term.