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DerKrebs [107]
3 years ago
9

If m∠SKL=31° and m∠JKS=52°, what is the measure of ∠JKL?

Mathematics
1 answer:
AysviL [449]3 years ago
5 0

Answer:

the angle is 97 because in a triangle all the angles add up to 180 so if you add 52 + 31 it equals 83 then you subtract 83 from 180 and get 97

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Tell me the answer in slope intercept form
den301095 [7]

Answer:

y=-2x+4

Step-by-step explanation:

the y int is (0,4), so b in y=mx+b is 4

the slope is -2, so the m in y=mx+b is -2

so, y=-2x+4 is your equation

6 0
3 years ago
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Body armor provides critical protection for law enforcement personnel, but it does affect balance and mobility. The article "Imp
yKpoI14uk [10]

Answer:

No, there is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that true average task time with armor is less than 2 seconds.

Then, the null and alternative hypothesis are:

H_0: \mu=2\\\\H_a:\mu< 2

The significance level is 0.01.

The sample has a size n=52.

The sample mean is M=1.95.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.2}{\sqrt{52}}=0.028

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1.95-2}{0.028}=\dfrac{-0.05}{0.028}=-1.803

The degrees of freedom for this sample size are:

df=n-1=52-1=51

This test is a left-tailed test, with 51 degrees of freedom and t=-1.803, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.039) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

3 0
3 years ago
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olya-2409 [2.1K]

Answer:

The equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e. \log _3\left(-2x-3\right)=2  has x = –6 as the solution.

Step-by-step explanation:

<u>Checking the equation</u>

log Subscript 3 Baseline (negative 2 x minus 3) = 2

Writing in algebraic expression

\log _3\left(-2x-3\right)=2

Use the logarithmic definition

\mathrm{If}\:\log _a\left(b\right)=c\:\mathrm{then}\:b=a^c

\log _3\left(-2x-3\right)=2\quad \Rightarrow \quad \:-2x-3=3^2

-2x-3=3^2

-2x-3=9

-2x=12

\mathrm{Divide\:both\:sides\:by\:}-2

\frac{-2x}{-2}=\frac{12}{-2}

x=-6

Therefore, the equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e. \log _3\left(-2x-3\right)=2  has x = –6 as the solution.

3 0
3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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