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2 years ago

9

Tara's pool is 50 yards in length and 20 feet in width. How many square feet is the pool? How many square yards in the pool? Sho

w your work.

1 answer:

zloy xaker [14]2 years ago

8 0

1 yard = 3 feet 3 x 50 = 150 ft. L x W = Area

150’x 20’ = 3,000 sq. ft. 3,000 sq ft. divided by 3 = 1,000 sq. yd.

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4 Gears A and B turn together. Gear A turns 20 times when

aleksandr82 [10.1K]

Answer:

90 turns

Step-by-step explanation:

<u>Ratio of turns</u>

A/B = 20/30 = 2/3

<u>If A = 60 then the ratio is</u>

60/B = 2/3 ⇒ B = 60*3/2 = 90

5 0

2 years ago

A motorcycle cost $12,000 when it was purchased. The value of a motorcycle decreases by 6% each year. Find the rate of decay eac

dalvyx [7]

<span>the rate of decay each month can calculated using the following formula:
</span><span>
6%/year × 1 year/(12 months) = 0.5%/month
0.06 x 1/12 = 0.005/month
</span><span>So the 0.5% is the right answer.
I hope it helped.</span>

4 0

3 years ago

New codes to destroy the First Order are known to exist. With probability 0.6, the codes are hidden by Leia; with probability 0.

elixir [45]

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L) = probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H) = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore, the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

3 0

3 years ago

Write the equation of a line that passes through the points (−3, 7) and (3, 3)

Dennis_Churaev [7]

Step-by-step explanation:

You can write an equation of a line conveniently by point-slope form. It's in the form of $y -a = m(x -b)$ where $(b,a)$ is the coordinates of a point that's on the line and $m$ is the slope of the line.

Now choose a point (It doesn't really matter which one) and plug that in the equation. I'll choose $(-3,7)$ where $a = 7$ and $b = -3$

$y -a = m(x -b) \\ y -7 = m(x -(-3)) \\ y -7 = m(x +3)$

The next thing we have to do now is finding the slope, $m$ , where it's equal to $\frac{y_{2} -y_{1}}{x_{2} -x_{1}}\\$ . I'll make $(-3,7)$ point 1 and $(3,3)$ point 2.

$m = \frac{3 - 7}{3 -(-3)} \\ m = \frac{3 - 7}{3 +3} \\ m = \frac{-4}{6} \\ m = -\frac{2}{3}$

Now let's plug that to our equation.

$y -7 = m(x +3) \\ y -7 = -\frac{2}{3}(x +3)$

Now we have the equation but out of all the choices it seemed that all of them are in slope-intercept form all you have to do now is make our equation rewrite it in slope-intercept form.

$y -7 = -\frac{2}{3}(x +3)\\ y -7 = -\frac{2}{3}x -\frac{2}{3}(3) \\ y - 7 = -\frac{2}{3}x -2\\ y = -\frac{2}{3}x +5$

<h3>Answer:</h3>

$y = -\frac{2}{3}x +5\\$ is your equation.

3 0

2 years ago

5 1/3 + -3 9/16. 5 1/3 + -3 + 9/18

ohaa [14]

Name them as vertices A,B,C , D and E in that order.

5 0

3 years ago