A lasagna recipe that serves 6 people calls for 1 pound of pasta 1.5pounds of meat 2 cups of cheese and 2 cups of sauce

Yeah I don’t get this

umka2103 [35]

using pythagorean theorem

a^2 + b^2 = c^2

(12x)^2 + (16x)^2 = 10^2

square each term

144x^2 + 256x^2 = 100

combine like terms

400 x^2 = 100

divide by 400 on each side

x^2 = 1/4

take the square root on each side

x = 1/2

Answer: x=1/2

8 0

3 years ago

Jane moved from a house with 72 square feet of closet space to an apartment with 44.64 square feet of closet space. What is the

Rashid [163]

Answer:

c. 38$

Step-by-step explanation:

6 0

2 years ago

One researcher wishes to estimate the mean number of hours that high school students spend watching tv on a weekday. a margin of

PtichkaEL [24]

Margin of error, e = Z*SD/Sqrt (N), where N = Sample population

Assuming a 95% confidence interval and substituting all the values;
At 95% confidence, Z = 1.96

Therefore,
0.23 = 1.96*1.9/Sqrt (N)

Sqrt (N) = 1.96*1.9/0.23

N = (1.96*1.9/0.23)^2 = 262.16 ≈ 263

Minimum sample size required is 263 students.

3 0

3 years ago

Read 2 more answers

A certain square is to be drawn on a coordinate plane. One of the vertices must be on the origin, and the square is to have an a

Scrat [10]

Answer:

The answer is (C) 8

Step-by-step explanation:

First, let's calculate the length of the side of the square.

$A_{square}=a^2$ , where $a$ is the length of the side. Now, let's try to build the square. First we need to find a point which distance from (0, 0) is 10. For this, we can use the distance formula in the plane:

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$ which for $x_1=0$ and $y_1 = 0$ transforms as $d=\sqrt{(x_2)^2 + (y_2)^2}$ . The first point we are looking for is connected to the origin and therefore, its components will form a right triangle in which, the Pythagoras theorem holds, see the first attached figure. Then, $x_2$ , $y_2$ and 10 are a Pythagorean triple. From this, $x_2= 6$ or $x_2=8$ while $y_2= 6$ or $y_2=8$ . This leads us with the set of coordinates:

$(\pm 6, \pm 8)$ and $(\pm 8, \pm 6)$ . (A)

The next step is to find the coordinates of points that lie on lines which are perpendicular to the lines that joins the origin of the coordinate system with the set of points given in (A):

Let's do this for the point (6, 8).

The equation of the line that join the point (6, 8) with the origin (0, 0) has the equation $y = mx +n$ , however, we only need to find its slope in order to find a perpendicular line to it. Thus,

$m = \frac{y_2-y_1}{x_2-x_1} \\m = \frac{8-0}{6-0} \\m = 8/6$

Then, a perpendicular line has an slope $m_{\bot} = -\frac{1}{m} = -\frac{6}{8}$ (perpendicularity condition of two lines). With the equation of the slope of the perpendicular line and the given point (6, 8), together with the equation of the distance we can form a system of equations to find the coordinates of two points that lie on this perpendicular line.

$m_{\bot}=\frac{6}{8} = \frac{8-y}{6-x}\\ 6(6-x)+8(8-y)=0$ (1)

$d^2 = \sqrt{(y_o-y)^2+(x_o-x)^2} \\(10)^2=\sqrt{(8-y)^2+(6-x)^2}\\100 = \sqrt{(8-y)^2+(6-x)^2}$ (2)

This system has solutions in the coordinates (-2, 14) and (14, 2). Until here, we have three vertices of the square. Let's now find the fourth one in the same way we found the third one using the point (14,2). A line perpendicular to the line that joins the point (6, 8) and (14, 2) has an slope $m = 8/6$ based on the perpendicularity condition. Thus, we can form the system:

$\frac{8}{6} =\frac{2-y}{14-x} \\8(14-x) - 6(2-y) = 0$ (1)

$100 = \sqrt{(14-x)^2+(2-y)^2}$ (2)

with solution the coordinates (8, -6) and (20, 10). If you draw a line joining the coordinates (0, 0), (6, 8), (14, 2) and (8, -6) you will get one of the squares that fulfill the conditions of the problem. By repeating this process with the coordinates in (A), the following squares are found:

(0, 0), (6, 8), (14, 2), (8, -6)

(0, 0), (8, 6), (14, -2), (6, -8)
(0, 0), (-6, 8), (-14, 2), (-8, -6)
(0, 0), (-8, 6), (-14, -2), (-6, -8)

Now, notice that the equation of distance between the two points separated a distance of 10 has the trivial solution $(\pm10, 0)$ and $(0, \pm10)$ . By combining this points we get the following squares:

(0, 0), (10, 0), (10, 10), (0, 10)
(0, 0), (0, 10), (-10, 10), (-10, 0)
(0, 0), (-10, 0), (-10, -10), (0, -10)
(0, 0), (0, -10), (-10, -10), (10, 0)

See the attached second attached figure. Therefore, 8 squares can be drawn

8 0

3 years ago

The sum of 6 and the product of 3 and d

Novosadov [1.4K]

Answer:

6 + 3d

Step-by-step explanation:

First, we can translate from English words to mathematical operations:

– Product: the result of multiplication

– Sum: the result of addition

So, we can rephrase the original sentence as “the result of adding 6 and (the result of multiplying 3 and d)”

When we multiply a constant like 3 by a variable like d, we usually write the two next to each other, which would be “3d” in this case. We can replace that last sentence in symbols with 6 + 3d

5 0

2 years ago