Answer:
12.5%
Step-by-step explanation:
2.56-2.24 =0.32
By using the rule of three we can find the answer.
we have that 2.56 = 100% so we have to find what percentage 0.32 represents
(0.32*100)/2.56 = 12.5
Answer:
Enter a problem...
Algebra Examples
Popular Problems Algebra Solve by Substitution 3x-4y=9 , -3x+2y=9
3
x
−
4
y
=
9
,
−
3
x
+
2
y
=
9
Solve for
x
in the first equation.
Tap for more steps...
x
=
3
+
4
y
3
−
3
x
+
2
y
=
9
Replace all occurrences of
x
in
−
3
x
+
2
y
=
9
with
3
+
4
y
3
.
x
=
3
+
4
y
3
−
3
(
3
+
4
y
3
)
+
2
y
=
9
Simplify
−
3
(
3
+
4
y
3
)
+
2
y
.
Tap for more steps...
x
=
3
+
4
y
3
−
9
−
2
y
=
9
Solve for
y
in the second equation.
Tap for fewer steps...
Move all terms not containing
y
to the right side of the equation.
Tap for more steps...
x
=
3
+
4
y
3
−
2
y
=
18
Divide each term by
−
2
and simplify.
Tap for more steps...
x
=
3
+
4
y
3
y
=
−
9
Replace all occurrences of
y
in
x
=
3
+
4
y
3
with
−
9
.
x
=
3
+
4
(
−
9
)
3
y
=
−
9
Simplify
3
+
4
(
−
9
)
3
.
Tap for more steps...
x
=
−
9
y
=
−
9
The solution to the system of equations can be represented as a point.
(
−
9
,
−
9
)
The result can be shown in multiple forms.
Point Form:
(
−
9
,
−
9
)
Equation Form:
x
=
−
9
,
y
=
−
9
image of graph
Answer:
it is 34 that's the answer.
Step-by-step explanation:
A. Constant of proportionality in this proportional relationship is; k=5
B. Equation to represent this proportional relationship is : c=t/k
Step-by-step explanation:
A.Given that : the amount she pays each month for international text messages is proportional to the number of international texts she sends, then
$3.20 k = 16 ---------where k is the constant of proportionality
k= 16/3.20 =5
k=5
B. Let c be the cost of sending the texts per month and t be the number of texts sent per month , so
c=t/k
c=t/5 ---------- is the proportionality relationship.
For t=16 , c= 16/5 =$3.20
Learn More
Proportionality :brainly.com/question/11490054
Keywords: cell phone plan, month, international texts, proportional,paid
#LearnwithBrainly
We can see that there are 5 CDs, each of radius 9 cm
<u>Area occupied by 1 disc:</u>
Area of a circle = πr²
Area of disc = π(9)²
Area of disc = 3.14 * 81 = 254 cm²
<u>Area occupied by 5 discs:</u>
Area occupied by 5 discs = Area occupied by 1 disc * 5
Area occupied by 5 discs = 254 * 5
Area occupied by 5 discs = 1270 cm²