All categories

3 years ago

WHOS GOOD AT GEO PLEASE HELP ME!!!!!

Mathematics

2 answers:

shutvik [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Gemiola [76]3 years ago

5 0

From the total 1000 students, 450 are male, so 1000 - 450 = 550 students are female.

117 students are both [enrolled in extracurriculars] and [female].

The total number of [female] students is equal to the total number of [female AND enrolled] students plus the total number of [female AND not enrolled] students. The events of being enrolled in extracurriculars and not being enrolled are mutually exclusive. So if x is the number of female students not enrolled in extracurriculars, then

550 = x + 117

x = 550 - 117

x = 433

and the answer is B.

You might be interested in

!Extremely Urgent!

ira [324]

Answer:

B. slope: 3/2, y-intercept: 5

Step-by-step explanation:

Rewrite in slope-intercept form. The slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.

3 0

3 years ago

14 Type the correct answer in each box. Use numerals instead of words. a Ava, Lucas, and Maria are playing a game where they pas

jeka94

Answer:

Maria–Ava: 15.7 feet
Lucas–Maria: 10.1 feet
angle at Maria: 50°

Step-by-step explanation:

The cosine and tangent functions are useful here. The relevant relations are ...

Cos = Adjacent/Hypotenuse

Tan = Opposite/Adjacent

The distance from Maria to Ava (ma) is the hypotenuse of the triangle, so we have ...

cos(40°) = 12/ma

ma = 12/cos(40°) ≈ 12/0.76604 ≈ 15.7 . . . feet

The distance from Lucas to Maria (ml) is the side opposite the given angle, so we have ...

tan(40°) = ml/12

ml = 12·tan(40°) ≈ 12·0.83910 ≈ 10.1 . . . feet

The angle formed at Maria's position is the complement of the other acute angle in the right triangle:

M = 90° -40° = 50°

In summary, ...

Maria–Ava: 15.7 feet
Lucas–Maria: 10.1 feet
angle at Maria: 50°

5 0

2 years ago

What is 1-2sin^2x=sinx Please show steps and find all solutions in interval [0,2pi)

Svetlanka [38]

Answer:

$\large\boxed{x=\dfrac{3\pi}{2}\ \vee\ x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}}$

Step-by-step explanation:

$1-2\sin^2x=\sin x\\\\\text{substitute}\ t=\sin x,\ t\in[-1,\ 1]\\\\1-2t^2=t\qquad\text{subtract t from both sides}\\\\-2t^2-t+1=0\qquad\text{change the signs}\\\\2t^2+t-1=0\\\\2t^2+2t-t-1=0\\\\2t(t+1)-1(t+1)=0\\\\(t+1)(2t-1)=0\iff t+1=0\ \vee\ 2t-1=0\\\\t+1=0\qquad\text{subtract 1 from both sides}\\\boxed{t=-1}\\\\2t-1=0\qquad\text{add 1 to both sides}\\2t=1\qquad\text{divide both sides by 2}\\\boxed{t=\dfrac{1}{2}}$

$\sin x=-1\to x=-\dfrac{\pi}{2}+2k\pi,\ k\in\mathbb{Z}\\\\\sin x=\dfrac{1}{2}\to x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}\\\\x\in[0,\ 2\pi)$

$x=-\dfrac{\pi}{2}\notin[0,\ 2\pi)\\\\x=-\dfrac{\pi}{2}+2\pi=\dfrac{3\pi}{2}\in[0,\ 2\pi)\\\\x=-\dfrac{\pi}{2}+4\pi=\dfrac{7\pi}{2}\notin[0,\ 2\pi)\\\\x=\dfrac{\pi}{6}\in[0,\ 2\pi)\\\\x=\dfrac{\pi}{6}+2\pi=\dfrac{13\pi}{6}\notin[0,\ 2\pi)\\\\x=\dfrac{5\pi}{6}\in[0,\ 2\pi)\\\\x=\dfrac{5\pi}{6}+2\pi=\dfrac{17\pi}{6}\notin[0,\ 2\pi)$