Question

The unbalanced equation below shows the reaction between sodium and water. In the reaction,

Answer 1

Answer:

41.4 g

Explanation:

2Na(s) + 2H2O (l) ----> 2NaOH ( aq) + H2 (g)

According to the above balnced chemical equation the ratio between moles of H2 gas formed to moles of Na used up is 1:2

Molar mass ( Mass of 1 mol) Of H2 gas is 2 gmol-1

So in 1.8 g of H2 0.9 mol should be present

Therefore no. of moles of Na used should be 2× 0.9 = 1.8 moles

Molar mass of Na= 23 gmol-1

So mass of 1.8 mol of Na = 1.8× 23 g = 41.4g