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Novay_Z [31]
3 years ago
14

The atomic theory has been revised many times over the last several hundred years. John Dalton described the atom as a solid sph

ere while later scientists such as J.J. Thomson and Ernest Rutherford developed different models of the atom.
Why has the atomic theory changed so much over the last several centuries?
A new scientific method helps scientists form more efficient theories and models.
As new discoveries are made, existing theories are revised or replaced.
The atom has changed over time, and new theories must reflect those changes.
Scientists with different opinions
Chemistry
2 answers:
frez [133]3 years ago
6 0
<span>As new discoveries are made, existing theories are revised or replaced.</span>
gizmo_the_mogwai [7]3 years ago
4 0

The answer is: As new discoveries are made, existing theories are revised or replaced.

Dalton stated that atom is matter that can not be divided.

His "plum pudding" model (1904) suggested: the electrons are embedded in the positive charge.  

J. J. Thomson discovered the electron in 1897.  

According to Rutherford model of the atom:  

1) Atoms have their charge concentrated in a very small nucleus.  

2) Major space in an atom is empty.  

3) Atoms nucleus is surrounded by negatively charged particles called electrons.  

4) An atom is electrically neutral.

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Why is it impossible to ever prove that a hypothesis is true?
maria [59]

Answer: A

Explanation:

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4 years ago
Which of the following would have similar properties to sodium (Na)?
bogdanovich [222]

Answer:

C

Explanation:

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A) Neon (Group 8a)(Group 18)

B) Magnesium (Group 2a)(Group 2)

C) Cesium (Group 1a)(Group 1)

D) Phosphorous (Group 5a)(Group 15)

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Explain how condensation is invovled in the water cycle
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8 0
3 years ago
Calculate the pH of a 0.2 M * 4 solution for which Kb = 1.8*10^-5 at 26 c . The equation for the reaction
lara31 [8.8K]

<u>Answer:</u> The pH of the solution is 11.24

<u>Explanation:</u>

We are given:

Molarity of ammonia = 0.2 M

K_b=1.8\times 10^{-5}

The given chemical equation follows:

                NH_3+H_2O\rightleftharpoons NH_4^++OH^-

I:                0.2

C:               -x                      +x        +x

E:             0.2-x                     x          x

The expression for equilibrium constant follows:

K_b=\frac{[NH_4^+][OH^-]}{[NH_3]}

Putting values in above expression, we get:

1.8\times 10^{-5}=\frac{x^2}{0.2-x}\\\\1.8\times 10^{-5}(0.2-x)=x^2\\\\x^2+(1.8\times 10^{-5}x)-(0.36\times 10^{-5})=0\\\\x=1.88\times 10^{-3}, 1.9\times 10^{-3}

Neglecting the negative value of x as concentration cannot be negative.

So, [OH^-]=x=1.88\times 10^{-3}M

pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution.

pOH=-\log [OH^-]

Putting values in above equation, we get:

pOH=-\log (1.88\times 10^{-3})\\\\pOH=2.76

We know:

pH+pOH=14\\\\pH=14-2.76\\\\pH=11.24

Hence, the pH of the solution is 11.24

6 0
3 years ago
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