Answer:
Step-by-step explanation:
For , we have two cases:
Therefore, for , we have the following cases:
Solving, we have:
.
Therefore,
I think its on the paper but not sure
Answer:
C. 97.5 yd
Step-by-step explanation:
The distance between Marsha, the ball and the tee for the fourth hole, forms a triangle.
Thus, the distance between Marsha's ball and the hole can be calculated using the Cosine formula below:
c² = a² + b² - 2abcos(C)
Where,
c = distance between Marsha's ball and the hole = ?
a = distance between the tee for the fourth hole and the tee = 300 yd
b = distance between tee and the hole = 255 yd
C = 18°
c² = 300² + 255² - 2(300)(255)cos(18)
c² = 90000 + 65025 - 153000 × 0.951
c² = 155025 - 145503
c² = 9522
c = √9522 ≈ 97.5
c = distance between Marsha’s ball and the hole = 97.5 yd (nearest tenth)
Answer:
one time
Step-by-step explanation:
because after that you would subtract by 20
Answer: I x^2 y^3 z
Step-by-step explanation:
This is the one most simplified. I’ll tell you why the others are incorrect.
F) 3^5 x^2 can be simplified. 3^5= 243. The simplified answer would be 243 x^2
G) (5y)^3= 125y^3
H) a^0 b (^0= 1 always) -> ab
Hope this helps!