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3 years ago

The Lewis structure for methane, CH4 is shown. How many valence electrons does each hydrogen atom in the molecule have?

Chemistry

1 answer:

TEA [102]3 years ago

7 0

Answer:

The answer to your question is below.

Explanation:

Hydrogen is located in group IA of the periodic table, then its valence number is 1.

Carbon is located in group IVA, then it has 4 valence electrons.

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the bunsen burners in your labs are fueled by natural gas which is mostly methane. the thermochemical equation for the combustio

vampirchik [111]

Answer:

CH₄ + 2O₂ —> CO₂ + 2H₂O

Explanation:

The thermochemical equation for the combustion of methane can be obtained as follow:

Methane (CH₄) under goes combustion in the presence of air (O₂) to produce carbon dioxide (CO₂) and water (H₂O). This can be represented in the equation below:

CH₄ + O₂ —> CO₂ + H₂O

Thus, we can balance the equation as follow:

CH₄ + O₂ —> CO₂ + H₂O

There are 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of H₂O as shown below:

CH₄ + O₂ —> CO₂ + 2H₂O

There are a total of 4 atoms of O on the right side and 1 atom on the left side. It can be balance by putting 2 in front of O₂ as shown below:

CH₄ + 2O₂ —> CO₂ + 2H₂O

Now the equation is balanced.

5 0

2 years ago

Predict whether a reaction occurs, and write balanced complete and net ionic equations:(a) Iron (III) chloride (aq) + cesium pho

Neporo4naja [7]

Answer : The balanced complete and net ionic equations are written below.

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a) The balanced molecular equation will be,

$FeCl_3(aq)+Cs_3PO_4(aq)\rightarrow 3CsCl(aq)+FePO_4(s)$

The complete ionic equation in separated aqueous solution will be,

$Fe^{3+}(aq)+3Cl^{-}(aq)+3Cs^{+}(aq)+PO_4^{3-}(aq)\rightarrow 3Cs^{+}(aq)+3Cl^{-}(aq)+FePO_4(s)$

In this equation the species present are, $3Cl^{-}\text{ and }Cs^{+}$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Fe^{3+}(aq)+PO_4^{3-}(aq)\rightarrow FePO_4(s)$

(b) The balanced molecular equation will be,

$2NaOH(aq)+Cd(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+Cd(OH)_2(s)$

The complete ionic equation in separated aqueous solution will be,

$2Na^{+}(aq)+2OH^{-}(aq)+Cd^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^{+}(aq)+2NO_3^{-}(aq)+Cd(OH)_2(s)$

In this equation the species present are, $Na^{+}\text{ and }NO_3^{-}$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Cd^{2+}(aq)+2OH^{-}(aq)\rightarrow Cd(OH)_2(s)$

(c) The balanced molecular equation will be,

$MgBr_2(aq)+2CH_3COOK(aq)\rightarrow (CH_3COO)_2Mg(aq)+2KBr(aq)$

The complete ionic equation in separated aqueous solution will be,

$Mg^{2+}(aq)+2Br^{-}(aq)+2K^{+}(aq)+2CH_3COO^{-}(aq)\rightarrow Mg^{2+}(aq)+2CH_3COO^{-}(aq)+2Br^{-}(aq)+2K^{+}(aq)$

In this equation all the species are the spectator ions.

Thus, there is no net ionic equation.

(d) The balanced molecular equation will be,

$Ag_2SO_4(aq)+BaCl_2(aq)\rightarrow 2AgCl(s)+BaSO_4(s)$

The complete ionic equation in separated aqueous solution will be,

$2Ag^{+}(aq)+SO_4^{2-}(aq)+Ba^{2+}(aq)+2Cl^{-}(aq)\rightarrow 2AgCl(s)+BaSO_4(s)$

In this equation no species are the spectator ions.

Thus, there is no net ionic equation.

(e) The balanced molecular equation will be,

$Na_2SO_4(aq)+Sr(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+SrSO_4(s)$

The complete ionic equation in separated aqueous solution will be,

$2Na^{+}(aq)+SO_4^{2-}(aq)+Sr^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^{+}(aq)+2NO_3^{-}(aq)+SrSO_4(s)$

In this equation the species present are, $Na^{+}\text{ and }NO_3^{-}$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Sr^{2+}(aq)+SO_4^{2-}(aq)\rightarrow SrSO_4(s)$

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3 years ago

In which of the substances in Figure 3-1 are the forces of attraction among the particles so weak that they can be ignored under

yawa3891 [41]

Substance C can be compared with gaseous particles in which intermolecular forces are so weak because particles are far from each other.
Hence option C is correct.

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3 years ago

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Answer:

108 grams

Explanation:

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2 years ago

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2 years ago

The Lewis structure for methane, CH4 is shown. How many valence electrons does each hydrogen atom in the molecule have?​

The Lewis structure for methane, CH4 is shown. How many valence electrons does each hydrogen atom in the molecule have?