What volume of 6.58M HCI is needed to make 500. mL of 3.00M HCI?

Chemistry

1 answer:

zmey [24]3 years ago

3 0

Answer:

228 mL

Explanation:

M1*V1 = M2*V2

M1 = 6.58 M

V1 = ?

M2 = 3.00 M

V2 = 500 mL

V1 = M2*V2/M1 = 3.00M*500.mL/6.58 M = 228 mL

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