Question

Write a linear equation that passes through the point (-3,3) and (9,-13)

Answer 1

Answer:

y=-4/3x-1

Step-by-step explanation:

$\frac{ {y}^{2} - {y}^{1} }{ {x}^{2 -{x}^{1} } }$

$\frac{ - 13 - 3}{9 - - 3} = \frac{ - 16}{12\ }$

y=mx+b like this:

y=-4/3x+b

To find b:

y=-4/3x+b. 

You can use either (x,y) point you want..the answer will be the same

(-3,3). y=mx+b or 3=-4/3 × -3+b, or solving for b: b=3-(-4/3)(-3). b=-1.

(9,-13). y=mx+b or -13=-4/3 × 9+b, or solving for b: b=-13-(-4/3)(9). b=-1.