Given:
Sides of triangles in the options.
To find:
Which could NOT be the lengths of the sides of a triangle.
Solution:
Condition for triangle:
Sum of two smaller sides of a triangle must be greater than the longest side.
In option A,
Sides 5 in, 5 in, 5 in are the lengths of the sides of a triangle.
In option B,
Sides 10 cm, 15 cm, 20 cm are the lengths of the sides of a triangle.
In option C,
Sides 3 in, 4 in, 5 in are the lengths of the sides of a triangle.
In option D,
Since, the sum of two smaller sides is less than the longest side, therefore the sides 8 ft, 15 ft, 5 ft are not the lengths of the sides of a triangle.
Therefore, the correct option is D.
Answer:
A. -2, 1
Step-by-step explanation:
Observe the chart and see where the f(x) and g(x) intersect.
When x=-2, f(-2)=g=(-2) and when x=1, f(1)=g=(1).
Answer:
x=1
Step-by-step explanation:
By substituting 1 into the equation for x, both sides will equal 8.
Answer:
A = 624
B = 14.76 or 14.8 or 15inches
Standard form in polynomial for Area = 26 x 24 = .624in^2.....
2(5 + 8) x 2( 5 + 7)
26 x 24 = 624 in^2
This is because the rectangle width indifference is 1/10th of the length measuring 2inches more, then we see both sides of the frame are equal to 2inches and match this measure for x = 2inches both width and length. We add 4 to each side 22 x 20 + 4x^2 we separate 4x^2 into 4x both sides, this has become 26 x 24 = 624in^2
as 4 was added each side.
Question 2.
We find the width is shown left to right in rectangles, they are the sides.
So Area 4 x 24 = 96in^2
or 6.5 of the 24 = 24/6.5 = 3.69 inches
26 /6.5 = scale of 6.5: 26 = 4 inches
Therefore Area = 3.69 x 4 = 14.76
if it was square frame it would be 16inches
Go for 14.76in^2 as ithe question says 4 inches and it becomes, a replaced width only and it must be still to scale as shown above with 24/6.5 = 3.69 so 3,69 x 4 = 14.76. Last resort would be that the length as kept at 24 x 4 = 96 and in this response it does exactly what the question asks the width changes only.
Answer:
n = 22
Step-by-step explanation:
Using
n = p(1-p)(Zc/E)²
From table E = 0.2 while p= 0.37
So substituting
We have n= 22.4
Thats a sample size of approximately 22
