Answer:
The output is 28
Explanation:
Required
Determine the output of the code segment
The first line initializes "answer" to 0
The next two lines iterate through lists [2,4] and [3,5
Each of these lists have two elements; So, the number of iterations is 2 * 2 i.e. 4.
In the first iteration
numA = 2, numB = 3, answer = 0
So:

In the second iteration
numA = 2, numB = 5, answer = 5
So:

In the third iteration
numA = 4, numB = 3, answer = 12
So:

In the fourth iteration
numA = 4, numB = 5, answer = 19
So:

Lastly, the value of "answer" is printed
<em>Hence, the output is 28</em>
A tornado happens when you mix cold with hot
1.)
<span>((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) </span>
<span>The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. </span>
<span>For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. </span>
<span>a.) (i <= n) || (i >= n) </span>
<span>This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. </span>
<span>b.) (a[i] == 0) && (a[i-1] == 0) </span>
<span>This means that both of these terms are true. We substitute. </span>
<span>((i <= n) && true) || (((i >= n) && true)) </span>
<span>Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: </span>
<span>(i <= n) || (i >= n) </span>
<span>This is clearly always true. </span>
Maybe in atosave, Computers mostly save what your working on :3