Answer:
Biomes are a group of ecosystems sharing the same characteristics and are well adapted to the prevailing abiotic factors. Any earth surface that has got a very large ecological system characterized by dominant forms of plant and animal life forms adapted to the prevailing climate and other environmental factors is termed as a biome. Biomes include both the abiotic and biotic factors.
Explanation:
Answer is A. restriction enzyme
In biology ,Restriction enzyme is known as a scissor.
Explanation:
To find the number of atoms in each specie, we consider the coefficient and the subscript of each of the given atoms.
1. NaCl:
Na = 1 atom
Cl = 1 atom
2. CO₂
C = 1 atom
O = 2 atom
3. O₂
O = 2 atoms
4. C₆H₁₂O₆
C = 6 atoms
H = 12 atoms
O = 6 atoms
For the second part;
1. 2NaCl
Na = 2 atoms
Cl = 2 atoms
2. 3CO₂
C = 3 atoms
O = 6 atoms
3. 4O₂
O = 8 atoms
4. 2C₆H₁₂O₆
C = 12 atoms
H = 24 atoms
O = 12 atoms
Answer: simple inorganic molecules to sugar
Explanation:
Through the process of photosynthesis plants use the green coloured pigment named chlorophyll present in their leaves to trap sun light (solar energy) alongside other simple inorganic molecules like atmospheric carbon dioxide and water to produce sugar molecules (usually glucose) which is later stored as starch.
Answer:
See the explanation
Explanation:
Answer 1.
As given that in F1 all are short and white then it can be said according to Mendel's law that short and white are dominant over tall and purple.
Let S for short s for tall and W for white and w for purple allele.
So the genotype of short purple will be Ssww or SSww. So In first case Ssww self crossed then resultant offsprings will be,
................ Sw .................... sw
Sw ........ SSww ............. Ssww
sw ........ Ssww .............. ssww (tall and purple)
So from this 1/4 will be tall and purple while 3/4 will be short and purple.
In second case SSww only short purple progeny will appear.
Answer 2.
2. a) The female progeny will not show any trait because there are two X chromosome in females , so female offspring can be carrier but not show any trait in case of X- linked trait.
2. b) Half of male offsprings show trait because X is inherited from mother. So the chance of having X-linked recessive allele is 1/2.
2. c) The chance of having X linked affect allele in daughter is 1/2. So the chance of inheriting that X to son will be 1/2 so in total there is chance of 1/4 that son will be affected.
2. d) the chance of first child show this trait will be 1/4 in case of male offspring while 0 in case of female offspring.
Hope this helps!
