Answer:
There is also an attachment below
Explanation:
Since we are talking about binary search, let's assume that the items are sorted according to some criteria.
Time complexity of binary search is O(logN) in worst case, best case and average case as well. That means it can search for an item in Log N time where N is size of the input. Here problem talks about the item not getting found. So, this is a worst case scenario. Even in this case, binary search runs in O(logN) time.
N = 700000000.
So, number of comparisions can be log(N) = 29.3 = 29.
So, in the worst case it does comparisions 29 times
<span>To the computer f, this answer is because when reading the statement I assume that there is no type of connection and / or communication between the computer a and c; therefore to be profitable the computer c should return the package sending it back to computer f.</span>
Answer:
The statement in Python is:
print("The average pH of citrus fruits is ",avg_citrus_pH)
Java
System.out.print("The average pH of citrus fruits is "+avg_citrus_pH);
C++
cout<<"The average pH of citrus fruits is "<<avg_citrus_pH;
Explanation:
The programming language is not stated; so, I answered the question in 3 languages (Python, Java and C++)
Assume that avg_citrus_pH has been declared and initialized; all you need to do is invoke a print statement and then append the variable
In Python, use print()
In c++, use cout<<
In Java, use System.out.print()
So, the statements are:
Python:
print("The average pH of citrus fruits is ",avg_citrus_pH)
Java
System.out.print("The average pH of citrus fruits is "+avg_citrus_pH);
C++
cout<<"The average pH of citrus fruits is "<<avg_citrus_pH;
Answer:
D
Explanation:
All three of A, B and C are required to harden a host. Thus, All of the above makes the best option.
Hardening simply refers to making your data impossible to be penetrated. More like bulletproof.
To do this, ensure measures like
- Regular Program cleanup
- Patches management
- service pack installation
- service or usage policies
...among others.
Cheers
Answer:
The code will produce:-
2.4
Explanation:
In this code the result of the arithmetic operation is stored in the variable c.On evaluating the expression it divides 12.0 by 5 which results in 2.4 and it is stored in float variable c.Then it is printed on the screen using print statement.Since the c is double variable so the result will be a decimal number.
Hence the answer is 4.
