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tino4ka555 [31]
2 years ago
10

Please help me please help​

Mathematics
1 answer:
AveGali [126]2 years ago
4 0

Answer:

Can't see that lol

Step-by-step explanation:

Thanks for the 5 points <3

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Answer:

tan3x=√3

tan3x=tan60,tan(180+60)

3x=60,240

:.x=20,80is your answer.

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Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa
Nataly_w [17]

Answer:

The first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

coefficient of x^{2} in the expansion of (2+x - x^{2})^{6} = (240 - 192) = 48

Step-by-step explanation:

(2+x)^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})

= 6_{C_{0}} \times x^{0} \times 2^{6}  + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4} + terms involving higher powers of x

= 64 + 192 \times x^{1} + 240 \times x^{2} + terms involving higher powers of x

so, the first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

Again,

(2+x - x^{2})^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})

Now, by inspection,

the term x^{2} comes from k =5 and k = 6

for k = 5, the coefficient of  x^{2}  is , (-32) \times 6 = -192

for k = 6 , the coefficient of x^{2} is, 6_{C_{2}} \times 2^{4} = 240

so,   coefficient of x^{2} in the final expression = (240 - 192) = 48

3 0
2 years ago
Write the explicit rule,
meriva

Answer:

a_{n} = 20n + 12

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = 52 - 32 = 72 - 52 = 92 - 72 = 20

This indicates the sequence is arithmetic with explicit formula

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 32 and d = 20, thus

a_{n} = 32 + 20(n - 1) = 32 + 20n - 20 = 20n + 12

7 0
2 years ago
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