Answer:
The mass of copper = 208.26 grams.
Explanation:
Density = mass / volume
8.9 = mass / 23.4
mass = 8.9 * 23.4
= 208.26 grams.
Answer:
The molarity of the formed CaBr2 solution is 0.48 M
Explanation:
Step 1: Data given
Number of moles CaBr2 = 0.72 moles
Volume of water = 1.50 L
Step 2: Calculate the molarity of the solution
Molarity of CaBr2 solution = moles CaBr2 / volume water
Molarity of CaBr2 solution = 0.72 moles / 1.50 L
Molarity of CaBr2 solution = 0.48 mol / = 0.48 M
The molarity of the formed CaBr2 solution is 0.48 M
Answer:
Increasing the temperature
Explanation:
According to Le Chatelier's principle, "if any of the conditions of a system in equilibrium is changed, the system will adjust itself in order to annul the effect of the change".
Since the forward reaction is exothermic, this suggests that heat is given off in the reaction.
Increasing the temperature will favors the reverse process which is endothermic.
In going from the reactants to the the products, the reaction is deemed exothermic which suggests that it produces heat.
The backward reaction is endothermic i.e it absorbs heat. If the temperature is increased, this process will be favored and more reactants produced. Less of the diiodine pentoxide will form. There is a leftward shift of the equilibrium
This is an incomplete question, here is a complete question.
Calculate the volume in milliliters of a 1.29 mol/L iron(II) bromide solution that contains 275 mmol of iron(II) bromide . Round your answer to significant 3 digits.
Answer : The volume of iron(II) bromide solution is, 
Explanation : Given,
Concentration of iron(II) bromide = 1.29 mo/L
Moles of iron(II) bromide = 275 mmol = 0.275 mol
conversion used : 1 mmol = 0.001 mol
Now we have to calculate the volume of iron(II) bromide.
Now put all the given values in this formula, we get:
Thus, the volume of iron(II) bromide solution is,
