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lidiya [134]
3 years ago
5

Neutrons are found in the nucleus and separate the other particles so that the strong force can hold the nucleus together. Which

particles are positively charged and need to be separated so that they don't repel? A) electrons B) neutrons C) protons D) quarks
Chemistry
2 answers:
Elza [17]3 years ago
6 0

Answer : The correct answer is C) protons

The positively charged particle found in nucleus are protons . They need to be kept separated as if the protons of two different particles are brought together , due to same charge they will repel each other.

If electrons are considered , they carry negative charge on them and they are present outside nucleus . Neutron have no charge on it although they are present in nucleus .

Quarks are present in both neutrons and protons . They carry both positive and negative charges .

Hence we can say protons are the positively charges particles which need to be separated .

fiasKO [112]3 years ago
3 0
The answer is protons(it always has a positive charge)hope that helps. :)
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Lisa [10]

Answer:

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Explanation:

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7 0
3 years ago
Calculate ∆G ◦ r for the decomposition of mercury(II) oxide 2 HgO(s) → 2 Hg(ℓ) + O2(g) ∆H◦ f −90.83 − − (kJ · mol−1 ) ∆S ◦ m 70.
bagirrra123 [75]

Answer:

4. +117,1 kJ/mol

Explanation:

ΔG of a reaction is:

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For the reaction:

2 HgO(s) → 2 Hg(l) + O₂(g)

ΔHr: 2ΔHf Hg(l) + ΔHf O₂(g) - 2ΔHf HgO(s)

As ΔHf of Hg(l) and ΔHf O₂(g) are 0:

ΔHr: - 2ΔHf HgO(s) = <u><em>181,66 kJ/mol</em></u>

<u><em /></u>

In the same way ΔSr is:

ΔSr= 2ΔS° Hg(l) + ΔS° O₂(g) - 2ΔS° HgO(s)

ΔSr= 2* 76,02J/Kmol + 205,14 J/Kmol - 2*70,19 J/Kmol

ΔSr= 216,8 J/Kmol = <em><u>0,216 kJ/Kmol</u></em>

Thus, ΔGr at 298K is:

ΔGr = 181,66 kJ/mol - 298K*0,216kJ/Kmol

ΔGr = +117,3 kJ/mol ≈ <em>4. +117,1 kJ/mol</em>

<em></em>

I hope it helps!

5 0
3 years ago
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Oxana [17]

Answer:

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Explanation:

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3 0
3 years ago
How many grams of h2o are needed to produce 45g of NO
schepotkina [342]

We need (i) the stoichiometric equation, and (ii) the equivalent mass of dihydrogen.
Explanation:
1
2
N
2
(
g
)
+
3
2
H
2
(
g
)
→
N
H
3
(
g
)
11.27

g
of ammonia represents
11.27
⋅
g
17.03
⋅
g
⋅
m
o
l
−
1

=

?
?

m
o
l
.
Whatever this molar quantity is, it is clear from the stoichiometry of the reaction that 3/2 equiv of dihydrogen gas were required. How much dinitrogen gas was required?
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