1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
3241004551 [841]
3 years ago
5

The vapor pressure of pure water at 25 °c is 23.8 torr. What is the vapor pressure (torr) of water above a solution prepared by

dissolving 18.0 g of glucose (a nonelectrolyte, mw = 180.0 g/mol) in 95.0 g of water?
Chemistry
1 answer:
maxonik [38]3 years ago
3 0

The vapour pressure of the solution is 23.4 torr.

Use <em>Raoult’s Law</em> to calculate the vapour pressure:  

<em>p</em>₁ = χ₁<em>p</em>₁°  

where  

χ₁ = the mole fraction of the solvent  

<em>p</em>₁ and <em>p</em>₁° are the vapour pressures of the solution and of the pure solvent  

The formula for vapour pressure lowering Δ<em>p</em> is  

Δ<em>p</em> = <em>p</em>₁° - <em>p</em>₁  

Δ<em>p</em> = <em>p</em>₁° - χ₁<em>p</em>₁° = p₁°(1 – χ₁) = χ₂<em>p</em>₁°  

where χ₂ is the mole fraction of the solute.  

<em>Step 1</em>. Calculate the <em>mole fraction of glucose </em>

<em>n</em>₂ = 18.0 g glu × (1 moL glu/180.0 g glu) = 0.1000 mol glu  

<em>n</em>₁ = 95.0 g H_2O × (1 mol H_2O/18.02 g H_2O) = 5.272 mol H_2O  

χ₂ = <em>n</em>₂/(<em>n</em>₁ + n₂) = 0.1000/(0.1000 + 5.272) = 0.1000/5.372 = 0.018 62  

<em>Step 2</em>. Calculate the <em>vapour pressure lowering</em>  

Δ<em>p</em> = χ₂<em>p</em>₁° = 0.018 62 × 23.8 torr = 0.4430 torr  

<em>Step 3</em>. Calculate the <em>vapour pressure</em>  

<em>p₁</em> = <em>p</em>₁° - Δ<em>p</em> = 23.8 torr – 0.4430 torr = 23.4 torr

You might be interested in
Which one of these is a gas<br> NaNo3<br> KL<br> KCL<br> NH3
Deffense [45]

Answer:

nano3 is a solid so its not that one it has to be NH3

Explanation:

welcome=.=!≧◇≦╰_╯←_←⊙▽⊙(ˇˍˇ)∩__∩◑__◐^_^^﹏^^m^^/^B-)(^o^)(ToT)

}

3 0
3 years ago
Calculate the fraction of atoms in a sample of argon gas at 400 K that have an energy of 10.0 kJ or greater.
nikdorinn [45]

Answer:

The answer to this can be arrived at by clculating the mole fraction of atoms higher than the activation energy of 10.0 kJ by pluging in the values given into the Arrhenius equation. The answer to this is 20.22 moles of Argon have energy equal to or greater than 10.0 kJ

Explanation:

From Arrhenius equation showing the temperature dependence of reaction rates.

K = Ae^{\frac{Ea}{RT} } where

k = rate constant

A = Frequency or pre-exponential factor

Ea   =       energy of activation

R = The universal gas constant

T = Kelvin absolute temperature

we have

f = e^{\frac{Ea}{RT} }

Where

f = fraction of collision with energy higher than the activation energy

Ea = activation energy = 10.0kJ = 10000J

R = universal gas constant = 8.31 J/mol.K

T = Absolute temperature in Kelvin = 400K

In the Arrhenius equation k = Ae^(-Ea/RT), the factor A is the frequency factor and the component e^(-Ea/RT) is the portion of possible collisions with high enough energy for a reaction to occur at the a specified temperature  

Plugging in the values into the equation relating f to activation energy we get

f = e^{\frac{10000J}{(8.31J/((mol)(K)))(400K)} } or f = e^{3.01} = 20.22 moles of argon have an energy of 10.0 kJ or greater

5 0
3 years ago
What is the mass in grams of 394 mL of ethylene glycol? Express your answer with the appropriate units.
AleksandrR [38]

Answer : The mass of ethylene glycol is, 437.34 grams

Solution : Given,

Volume of ethylene glycol = 394 ml

Density of ethylene glycol = 1.11 g/ml    (Standard value)

Formula used :

Density=\frac{Mass}{Volume}

Now put all the given values in this formula, we get the mass of ethylene glycol.

1.11g/ml=\frac{Mass}{394ml}

Mass=437.34g

Therefore, the mass of ethylene glycol is, 437.34 grams

3 0
3 years ago
Question<br> The first person to create an atomic model was
victus00 [196]
John Dalton created the very first atomic theory. Dalton viewed atoms as tiny, solid balls. Dalton was an English school teacher who performed many experiments on atoms. 1.
6 0
2 years ago
My friend Justin here is cracked at SWBF1 my guy ✊✊ <br> (25dkersey and kingboss2)
Mkey [24]

Answer:

battlefront is godly ;)

Explanation:

4 0
2 years ago
Read 2 more answers
Other questions:
  • The wavelength of a light wave can be used to measure which of the following
    11·1 answer
  • Consider the pka (3.75) of formic acid, h-cooh as a reference. with appropriate examples, show how inductive, dipole, and resona
    12·1 answer
  • Which of the following choices is an <br> example of gathering evidence
    7·1 answer
  • The reaction of pyrrole with bromine forms predominantly __________. View Available Hint(s) The reaction of pyrrole with bromine
    6·1 answer
  • How many electrons are in O2-?
    14·1 answer
  • How does energy transfer from the sun to earth and the atmosphere
    6·1 answer
  • Which substance gives heat and light after combustion?
    13·1 answer
  • Most bones are connected at Joints by​
    12·1 answer
  • What is the balanced form of the chemical equation shown below?
    7·1 answer
  • What layers are composed of metals? Choose all that apply.<br> Inner core<br> Outer core<br> Mantle
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!