Answer:
Step-by-step explanation:
The given relation between length and width can be used to write an expression for area. The equation setting that equal to the given area can be solved to find the shed dimensions.
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<h3>Given relation</h3>
Let x represent the width of the shed. Then the length is (2x+3), and the area is ...
A = LW
20 = (2x+3)(x) . . . . . area of the shed
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<h3>Solution</h3>
Completing the square gives ...
2x² +3x +1.125 = 21.125 . . . . . . add 2(9/16) to both sides
2(x +0.75)² = 21.125 . . . . . . . write as a square
x +0.75 = √10.5625 . . . . . divide by 2, take the square root
x = -0.75 +3.25 = 2.50 . . . . . subtract 0.75, keep the positive solution
The width of the shed is 2.5 feet; the length is 2(2.5)+3 = 8 feet.
Use the distributive property.
This states that: a(b+c)= ab+ac
So,
-6*a= -6a and -6*8= -48
-6a+-48
This is the most you can simplify this problem.
I hope this helps!
~kaikers
<span>Perimeter of a rectangle: 2(l + w)
</span>
2(l + w) ≥ 30 in
<span>
Simplify- divide both sides by 2.
l + w ≥ 15 in
Substitute (w + 3) into l so only 1 variable is used.
(w + 3) + w ≥ 15 in
Simplify further- add variables and subtract 3 from both sides.
2w ≥ 12 in
Divide both sides by 2.
w ≥ 6 in
Answer: D</span>
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