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arlik [135]
2 years ago
6

Suppose y varies directly with x, and y = 36 when x = 4. What is the direct variation?

Mathematics
1 answer:
Westkost [7]2 years ago
5 0

Answer:

the answer is 6 to y and to everything

Step-by-step explanation:

the answer is 6 to y and to everything

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Pls Help me answer these questions. Brainliest for the correct person who answers each question correctly.
ahrayia [7]
Q1.) A. 12
Q2.) A. \frac{7}{10}
Q3.) C. A probability near 1 indicates a likely event
Q4.) D. 5
6 0
3 years ago
Read 2 more answers
Least to greatest 52, 63, 55, 56, 62, 54, 59, 60, 53, 61, 88
BartSMP [9]

Answer:

52, 53, 54, 55, 56, 59, 60, 61, 62, 88

Step-by-step explanation:

You need to start from 52 to 88 (least to greatest) and then you will get answer.

7 0
2 years ago
Translate the sentence into an equation. Six more than the quotient of a number 5 and 9 equals . Use the variable y for the unkn
sashaice [31]
the answer is 6+5y=9
7 0
3 years ago
Describe the position of the function below relative to the graph of the indicated basic function.
matrenka [14]

From the given the option moved left 1 unit; reflected across the x axis is the correct.

what is function?

A function from a set X to a set Y in mathematics assigns each element of X exactly one element of Y. The set X is known as the function's domain, and the set Y is known as the function's codomain.

We have to describe the position of the function f(x) = -2^x^+^1 relative to the basic function 2^x.

Let the parent function is 2^x.

After shifting one unit right it becomes, 2^x^+^1.

After reflection in x axis it  becomes, -2^x^+^1.

Hence, from the given the option moved left 1 unit; reflected across the x axis is the correct.

To know more about function, click on the link

brainly.com/question/25638609

#SPJ1

7 0
1 year ago
​ A sample of n = 9 college students is used to evaluate the effectiveness of a new Study Skills Workshop. Each student’s grade
forsale [732]

Answer:

B) μD = 0.60 ± 0.10(1.397)

Step-by-step explanation:

The confidence interval is given by:

MD±t_{\alpha/2, n-1} \frac{s}{\sqrt{n} }

Where

MD=60

n=9

df=n-1=8

t_{\alpha/2, n-1}=1.397

s=\sqrt{0.09} =0.3

Then the confidence interval is

μD=0.60±1.397*(0.3/√9)

μD=0.60±0.10*(1.397)

6 0
3 years ago
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