Use lagrange multipliers to find the maximum and minimum

Explain how finding 7×20 is similar to finding 7×2000 then find each product

AURORKA [14]

You will get the same answers but with more zeros. For example 7x20 is 140, and 7x2000 is 14,000 but with more zero's

6 0

4 years ago

Use the definition of continuity and the properties of limits to show that the function

Zepler [3.9K]

Answer:

Applied the definition and the limit.

They had the same result, so the function is continuous.

Step-by-step explanation:

At function f(x) is continuous at x = a if:

$\lim_{x \to a} f(x) = f(a)$

In this question:

$f(x) = x^{2} + 5(x-2)^{7}$

At x = 3.

$\lim_{x \to 3} x^{2} + 5(x-2)^{7} = 3^{2} + 5(3-2)^{7} = 14$

$f(3) = 3^{2} + 5(3-2)^{7} = 14$

Since $\lim_{x \to 3} f(x) = f(3)$ , f(x) is continuous at x = 3.

7 0

3 years ago

A line has a slope of -4/5 . Which ordered pairs could be points on a line that is perpendicular to this line? Check all that ap

attashe74 [19]

I hope this helps you

3 0

3 years ago

Read 2 more answers

Plzzzzzzzz helppppp meeeeeeee

andriy [413]

The rectangle has an area of 18x8 = 144 sq in. The circle has an area of (pi)r^2 or (pi)3^2 =28.27sq in. Subtract 144 - 28.27 = 115.73

3 0

3 years ago

The chances of a tax return being audited are about 21 in 1 comma 000 if an income is less than $100,000 and 29 in 1 comma 000

vladimir2022 [97]

Answer:

a) p=0.021

b) p=0.029

c) Exactly one audit: P=0.0965

More than one audit: P=0.0042

Step-by-step explanation:

a) If the income is less than $100,000, there is a probability of 21 in 1,000 of being audited. This is:

$p_1=\dfrac{21}{1,000}=0.021$

If the income is equal or more than $100,000, there is a probability of 29 in 1,000 of being audited. This is:

$p_2=\dfrac{29}{1,000}=0.029$

b) If we have 5 taxpayers with incomes under $100,000, and we want to know the probability that exactly one will be audited, we can model this a binomial randome variable, with p=0.021 and n=5:

$P(x=1) = \dbinom{5}{1} p^{1}q^{4}=5*0.021*0.9186=0.0965\\\\$

There is a probability of 0.0965 that exactly one out of a sample of five taxpayers with incomes under $100,000 will be audited.

To calculate the probability that more than one will be audited, we use the same distribution:

$P(x>1)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0) = \dbinom{5}{0} p^{0}q^{5}=1*1*0.8993=0.8993\\\\\\P(x=1) = \dbinom{5}{1} p^{1}q^{4}=5*0.021*0.9186=0.0965\\\\\\P(x>1)=1-[P(x=0)+P(x=1)]\\\\P(x>1)=1-(0.8993+0.0965)\\\\P(x>1)=1-0.9958\\\\P(x>1)=0.0042$

There is a probability of 0.0042 that more than one out of a sample of five taxpayers with incomes under $100,000 will be audited.

8 0

3 years ago