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Mekhanik [1.2K]
3 years ago
8

Solve for z: -0.3z=-17.4-2.3z

Mathematics
1 answer:
OleMash [197]3 years ago
7 0

Answer:

z=-8.7

Step-by-step explanation:

-0.3z=-17.4-2.3z

10(-0.3z)=10(-17.4-2.3z)

-3z=-174-23z

20z=-174

z=-8.7

Check:

-0.3z=-17.4-2.3z

-0.3(-8.7)=-17.4-2.3(-8.7)

2.61=-17.4+20.01

2.61=2.61

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Answer:

ADB is the same as BDC because both sets of those angles make a triangle that look exactly the same. It has the same area and shape.

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4 years ago
7.RP.A.1 3. If 1 1/2 cups of something fills 2/3 of a container, how many cups fill the container? ​
Andreas93 [3]

Answer:

Hi there!

Your answer is:

2 & 1/4 <u>OR</u> 2.25 cups fills the container!

Step-by-step explanation:

If 1 & 1/2 (aka 3/2) fills 2/3 of the container, then:

we know that <em>half</em> of 3/2s fills 1/3 of the container

To find half of 3/2, we multiply 3/2 by the <em><u>inverse</u></em> of 2, which is 1/2.

3/2÷2

3/2×1/2 = 3/4 ths

Now that we know 3/4ths fills 1/3 of the container, we add that to 1& 1/2.

3/4+ 1&1/2 = 2 & 1/4

Check your work!

3/4 × 3 should equal 2&1/4 if we are correct

3/4 × 3/1 = 9/4.

Simplify!

9/4 = 2&1/4

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All 4 questions please
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Answer:

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Step-by-step explanation:

1.

S = 2\pi rh\\Divide\:both\sides\:of\:the\:equation\:by\:2rh\\\\\frac{S}{2rh} = \frac{2 \pi rh}{2 rh} \\\\\pi = \frac{S}{2rh}

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E = \frac{1}{2} mv^2\\\\E = \frac{mv^2}{2} \\\\Cross\:multiply\\\\2E =mv^2\\Divide\:both\:sides\:of\:the\:equation\:by\:m\\\frac{2E}{m} = \frac{mv^2}{m} \\\\\frac{2E}{m} =v^2\\Square\:root\:both\:sides\:of\:the\:equation\\\sqrt{\frac{2E}{m} } = \sqrt{v^2} \\\\\sqrt{\frac{2E}{m} } =v\\\\v =\sqrt{\frac{2E}{m} }

3.

7a+2b =c\\Isolate\:b\\\\2b =c-7a\\2b= -7a+c\\Divide\:both\:sides\:of\:the\:equation\:by \:2\\\frac{2b}{2} =\frac{-7a+c}{2} \\\\b = \frac{-7a+c}{2}

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Remark

At first glance, one would think this problem isn't possible. But if you use the magnifying glass, you see that it is.

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