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LenaWriter [7]
3 years ago
8

A 20-foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on level ground 6 feet

from the base of the building. How high up the wall does the ladder reach?
Mathematics
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

19.1 feet

Step-by-step explanation:

This forms a right triangle

use the pythagorean theorem

a^2 + b^2 = c^2

a^2 + 6^2 = 20^2

a^2 + 36 = 400

a^2 = 364

a = 19.0787840283

Rounded

19.1 feet

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almond37 [142]

Answer:

A

Step-by-step explanation:

That's the formula for the solution of a quadratic equation, like this:

a {x}^{2}  + bx   +  c = 0

The formula is:

x =  \frac{ - b± \sqrt{ {b}^{2} \:  - 4ac } }{2a}

In your case:

a = 7 \\ b =  - 5 \\ c =  - 2

The only answer that has c = -2 is the first one, A.

If you move the 5 to the left-hand side, it becomes -5 and with the +3 gives a -2.

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Please show work for both problems
sukhopar [10]

(1) The value of x is 25

(2) The measure of ∠CBD is 60°

Explanation:

(1) The given two angles are vertical angles. Since, vertical angles are equal, we can add the two angles to determine the value of x.

Thus, we have,

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(2) It is given that the measure of ∠ABC = (x+7)° and ∠CBD = (2x+14)°

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