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ikadub [295]
3 years ago
13

What is the electron configuration of a n3- anion?

Chemistry
1 answer:
asambeis [7]3 years ago
3 0

Answer:

You can see in the above illustration of the periodic table that N is in Period 4, Group 5A, and p-block. Before reaching N, you will pass through the atomic orbitals 1s, 2s, and 2p. The electron configuration of N3- is N3-: 1s22s22p6 .

Explanation:

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Compare and contrast Aufbau principle and the Pauli exclusion principle.
lapo4ka [179]

Answer: Pauli exclusion principle: only two electrons can occupy the same orbital and they must have opposite spin directions

Explanation:

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4 years ago
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4 years ago
How many milliliters of a 0.211 M HI solution are needed to reduce 24.0 mL of a 0.354 M KMnO4 solution according to the followin
Novay_Z [31]

Answer:

The answer to your question is 242 ml

Explanation:

Data

HI 0.211 M   Volume = x

KMnO₄ 0.354 M   Volume = 24 ml

Balanced Chemical reaction

     12HI + 2KMnO₄ + 2H₂SO₄ → 6I₂ + Mn₂SO₄ + K₂SO₄ + 8H₂O

Process

1.- Calculate the moles of KMnO₄  0.354 M in 24 ml

Molarity = moles / volume (L)

moles = Molarity x volume (L)

moles = 0.354 x 0.024

moles = 0.0085

2.- From the balanced chemical reaction we know that HI and KMnO₄ react in the proportion 12 to 2. Then,

              12 moles of HI --------------- 2 moles of KMnO₄

                x                     --------------- 0.0085 moles of KMnO₄

             x = (0.0085 x 12)/2

             x = 0.051 moles of HI

3.- Calculate the milliliters of HI 0.211 M

Molarity = moles/volume

Volume = moles/molarity

Volume = 0.051/0.211

Volume = 0.242 L or Volume = 242 ml

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4 years ago
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Answer:

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7 0
3 years ago
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How many milliliters of a 1.25 molar hydrochloric acid (HCl) solution would be needed to react completely with 60.0 grams of cal
stich3 [128]

<u>Answer:</u>

2400 mL

<u>Explanation:</u>

Ca + 2HCl \implies CaCl_2 + H_2

According to this equation, the stoichiometric ratio between Ca and HCl for the complete reaction is 1:2.

We know that the number of moles of Ca can be calculated using the mole formula. (<em>number of moles = mass / molar mass</em>)

Moles of Calcium = \frac{60}{40} = 1.5 mol

So the moles of HCl = 1.5 \times 2 = 3.0 mol

<em>Volume of HCl solution = Moles of HCl/ concentration of HCl</em>

Volume of HCl solution = \frac{3}{1.25} = 2400 mL

4 0
3 years ago
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