Answer:
0.42 M
Explanation:
The reaction that takes place is:
- Cu(CH₃COO)₂ + Na₂CrO₄ → Cu(CrO₄) + 2Na(CH₃COO)
First we <u>calculate the moles of Na₂CrO₄</u>, using the <em>given volume and concentration</em>:
(200 mL = 0.200L)
- 0.70 M * 0.200 L = 0.14 moles Na₂CrO₄
Now we <u>calculate the moles of Cu(CH₃COO)₂</u>, using its <em>molar mass</em>:
- 40.8 g ÷ 181.63 g/mol = 0.224 mol Cu(CH₃COO)₂
Because the molar ratio of Cu(CH₃COO)₂ and Na₂CrO₄ is 1:1, we can directly <u>substract the reacting moles of Na₂CrO₄ from the added moles of Cu(CH₃COO)₂</u>:
- 0.224 mol - 0.14 mol = 0.085 mol
Finally we <u>calculate the resulting molarity</u> of Cu⁺², from the <em>excess </em>cations remaining:
- 0.085 mol / 0.200 L = 0.42 M
True.
This is a combination of an anion and a cation to form a neutral compound.
60 i believe i haven't did science in a while sorry if im wrong though... ._.
Answer:
The answer is
<h2>2.64 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 611 g
volume = final volume of water - initial volume of water
volume = 256.7 - 25.1 = 231.6 mL
The density of the metal is
We have the final answer as
<h3>2.64 g/mL</h3>
Hope this helps you
when the half-life is the amount of time which the radioactive isotopes need to
be in half.
So when w start with 32 g of unobtanium 53 so :
1- after 20 sec the number of grams remain = 32/2
= 16 g
2- and after 40 sec the number of grams remain
16 g will cut in half:
= 16 / 2
= 8 g
3- and after 60 sec the number of grams remain
8 g will cut in half:
= 8g /2
= 4 g
4- and after 80 sec the number of grams remain
4 g will cut in half:
= 4 g /2
= 2 g
5-after 100 sec the number of grams remain
2 g will cut in half :
= 2g /2
= 0 g
after 100 sec there are no grams remain
