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Ulleksa [173]
3 years ago
8

Which term is defined as the change in the direction of light when it goes from one medium into a different medium?

Chemistry
2 answers:
Natali [406]3 years ago
4 0
1. is refraction 

2. Metal spoon 

3. strikes an object and bounces off of it

4. Electromagnetic/Light waves travel at different speeds through different media.

5.  The light wave is bending around an obstacle or through a barrier. 

6. Reflected light

7. A ring around the Sun caused by particles in the air.

8. Transmission is when light passes through an object and absorption is when some or all of the light is taken in or absorbed by the object.


Hope this helps 
ki77a [65]3 years ago
3 0
1.Reflection
2.medal spoons
3.strike an object and bounces off
4.d
and thats all ik

hope this helps!
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Compounds like CCl₂F₂ are known as chlorofluorocarbons, or CFCs. These compounds were once widely used as refrigerants but are n
Nataliya [291]

Explanation:

The given data is as follows.

        Specific heat of water = 4.18 J/g^{o}C

        Heat of fusion of water = 334 J/g

        Mass of water = 200 g

On bringing water at 0^{o}C, heat released will be as follows.

            q_{1} = m \times C \times \Delta T

                    = 200 g \times 4.18 J/g^{o}C \times (0 - 15)^{o}C

                    = -12540 J

or,                = -12.540 kJ           (as 1 kJ = 1000 J)

Now, calculate the heat releasedwhen water freezes at 0^{o}C as follows.

                q_{2} = mass \times \text{-heat of fusion}

                         = 200 g \times -334 J/g

                         = -66800 J

or,                      = -66.80 kJ

Therefore, total heat released in freezing water will be as follows.

                     q_{total} = q_{1} + q_{2}

                              = (-12.540 - 66.80) kJ

                              = -79.34 kJ

Hence,

       amount of heat released in freezing water = heat used to vaporize CCl_{2}F_{2}

Now, heat of vaporization of CCl_{2}F_{2} = 289 J/g

Total heat released in freezing water = -79.34 kJ

Heat consumed to vaporize CCl_{2}F_{2} = 79.34 kJ = -79340 J

Therefore, calculate the mass of CCl_{2}F_{2} vaporized as follows.

              Mass of CCl_{2}F_{2} vaporized = \frac{\text{heat consumed}}{\text{heat of vaporization}}

                              = \frac{79340 J}{289 J/g}

                              = 274.53 g

Thus, we can conclude that 274.53 g mass of this substance must evaporate to freeze 200 g of water initially at 15^{o}C.

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Answer:

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Explanation:

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1 mole of every substance contains a particle number of 6.02×10²³

From the question,

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1 mole of CH₄ has a mass of 16 g

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16 g of CH₄ contains 6.02×10²³ molecules

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Answer:

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