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LenKa [72]
4 years ago
9

If a 20.0mL test tube measures 15.0cm, what is the length in meters?

Chemistry
2 answers:
sergiy2304 [10]4 years ago
8 0

Answer : The length of the test tube in meter is 0.15 meter

Explanation :

The conversion used for length from centimeter to meter is:

1 cm = 0.01 m

As we are given the length of the test tube is, 15.0 cm. Now we have to determine the length of the test tube in meter.

As, 1 cm of length of the test tube = 0.01 meter

So, 15.0 cm of length of the test tube = \frac{15.0cm}{1cm}\times 0.01m=0.15m

Therefore, the length of the test tube in meter is 0.15 meter

Leokris [45]4 years ago
4 0

15.0 cm(1 m/100 cm) = 0.150 m Always include your units so you can tell what your final units will be.


Hoped I Helped

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So de fanga gu se si gage humang we sapa shata phoni we heo sang pai​
PilotLPTM [1.2K]

Answer:

Which language is this???

5 0
3 years ago
Given pH = 3.50 Find: [H3O+] and [OH-] Is this acidic, basic or neutral?
lys-0071 [83]

Answer:

Explanation:

Given parameters:

           pH = 3.50

Unknown:

    concentration of [H₃0⁺] = ?

    concentration of [OH⁻] = ?

Solution:

In order to find the unknown, we use some simple expressions which best explains the pH scale and the equilibrium systems of aqueous solutions.

         pH = -log₁₀[H₃O⁺]

         [H₃O⁺] = inverse log₁₀ (-pH) = 10^{-pH} = 10^{-3.5}

          [H₃O⁺] = 3.2 x 10⁻⁴moldm⁻³

       

For the  [OH⁻]:

       we use : pOH = -log₁₀ [OH⁻]

     Recall: pOH + pH = 14

                  pOH = 14 - pH = 14 - 3.5 = 10.5

  Now we plug the value of pOH into pOH = -log₁₀ [OH⁻]

                                   [OH⁻] = 10^{-pOH}

                        [OH⁻] = 10^{-10.5} = 3.2 x 10⁻¹¹moldm⁻³

The solution is acidic as the concentration of H₃0⁺ is more than that of the OH⁻ ions.

                   

8 0
3 years ago
Find the equation of the line passing through the points (2, 1) and (5, 10).​
Vedmedyk [2.9K]

The equation : y=3x-5

<h3>Further explanation </h3>

Straight-line equations are mathematical equations that are described in the plane of cartesian coordinates

General formula

y-y1 = m(x-x1)

or

y = mx + c

Where

m = straight-line gradient which is the slope of the line

x1, y1 = the Cartesian coordinate that is crossed by the line

c = constant

The formula for a gradient (m) between 2 points in a line

m = Δy / Δx

  • Gradient

\tt \dfrac{10-1}{5-2}=3

  • Equation

\tt y-1=3(x-2)\\\\y-1=3x-6\\\\y=3x-5

3 0
3 years ago
A potential energy diagram is shown.
Vesna [10]

Answer:

25kJ

Explanation:

Given the initial energy to be 30kJ

The energy change from the initial energy to the peak energy = (65-30) kJ

= 35kJ

since the second energy change was a drop in energy it is regarded negative

= (55-65)

= -10kJ

Therefore total energy change

= (35-10)kJ

= 25kJ

5 0
2 years ago
The chart below lists data on four different projects designed to restore a wetlands habitat destroyed by human activity and a r
snow_lady [41]

Answer:

Project 3.

Explanation:

Project 3's anticipated cost is 12 to 17 million dollars. It is a <em>lower </em>anticipated cost than Project 2 and Project 4, but <em>higher</em> than Project 1 by one million dollars at maximum cost anticipation. Additionally, the percentage of wildlife to benefit is 70-80%, which is <em>second</em> to the most wildlife to benefit which is Project 4 at 75-80%.

And finally, for community support for Project 3 - the chart lists it as high. This outclasses Project 2 and Project 4, but balances with Project 1. However, Project 1 costs 13 to 16 million dollars and <em>only</em> benefits 15-25% of wildlife.

5 0
2 years ago
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