Answer:
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If a 20.0mL test tube measures 15.0cm, what is the length in meters?
2 answers:
Answer : The length of the test tube in meter is 0.15 meter
Explanation :
The conversion used for length from centimeter to meter is:
1 cm = 0.01 m
As we are given the length of the test tube is, 15.0 cm. Now we have to determine the length of the test tube in meter.
As, 1 cm of length of the test tube = 0.01 meter
So, 15.0 cm of length of the test tube =
Therefore, the length of the test tube in meter is 0.15 meter
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Answer:
Explanation:
Given parameters:
pH = 3.50
Unknown:
concentration of [H₃0⁺] = ?
concentration of [OH⁻] = ?
Solution:
In order to find the unknown, we use some simple expressions which best explains the pH scale and the equilibrium systems of aqueous solutions.
pH = -log₁₀[H₃O⁺]
[H₃O⁺] = inverse log₁₀ (-pH) = =
[H₃O⁺] = 3.2 x 10⁻⁴moldm⁻³
For the [OH⁻]:
we use : pOH = -log₁₀ [OH⁻]
Recall: pOH + pH = 14
pOH = 14 - pH = 14 - 3.5 = 10.5
Now we plug the value of pOH into pOH = -log₁₀ [OH⁻]
[OH⁻] =
[OH⁻] = = 3.2 x 10⁻¹¹moldm⁻³
The solution is acidic as the concentration of H₃0⁺ is more than that of the OH⁻ ions.
The equation : y=3x-5
<h3>Further explanation </h3>Straight-line equations are mathematical equations that are described in the plane of cartesian coordinates
General formula
y-y1 = m(x-x1)
or
y = mx + c
Where
m = straight-line gradient which is the slope of the line
x1, y1 = the Cartesian coordinate that is crossed by the line
c = constant
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m = Δy / Δx
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