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LenKa [72]
4 years ago
9

If a 20.0mL test tube measures 15.0cm, what is the length in meters?

Chemistry
2 answers:
sergiy2304 [10]4 years ago
8 0

Answer : The length of the test tube in meter is 0.15 meter

Explanation :

The conversion used for length from centimeter to meter is:

1 cm = 0.01 m

As we are given the length of the test tube is, 15.0 cm. Now we have to determine the length of the test tube in meter.

As, 1 cm of length of the test tube = 0.01 meter

So, 15.0 cm of length of the test tube = \frac{15.0cm}{1cm}\times 0.01m=0.15m

Therefore, the length of the test tube in meter is 0.15 meter

Leokris [45]4 years ago
4 0

15.0 cm(1 m/100 cm) = 0.150 m Always include your units so you can tell what your final units will be.


Hoped I Helped

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3 years ago
Molybdenum has a molar mass of 95.94g/mol. How many molecules of molybdenum are in 150.0 g of molybdenum
Kitty [74]
We are given the molar mass of Molybdenum as 95.94 g/mol. Also, the chemical symbol for Molybdenum is Mo. This question is asking for the amount of molecules of molybdenum in a 150.0 g sample. However, since molybdenum is a metal and it is in the form of solid molybdenum, Mo (s), it is not actual a molecule. A molecule has one or more atom bonded together. We will instead be finding the amount of atoms of Molybdenum present in the sample. To do this we use Avogadro's number, which is the amount of atoms/molecules of a substance in 1 mole of that substance.

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5 0
3 years ago
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Alex777 [14]

Answer:

Iodide> Bromide > chloride > flouride

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In either case, the ease of departure of the leaving group is determined by the nature of the C-X bond. The stronger the C-X bond, the worse the leaving group will be in nucleophilic substitution. The order of strength of C-X bond is F>Cl>Br>I.

Hence, iodine displays the weakest C-X bond strength and it is thus, a very good leaving group in nucleophillic substitution while fluorine displays a very high C-X bond strength hence it is a bad leaving group in nucleophilic substitution.

Therefore, the ease of the use of halide ions as leaving groups follows the trend; Iodide> Bromide > chloride > flouride

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The molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

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So we can conclude that the molecule is stable and can exist even though the number of valence electrons around central atom in the molecule are less than 8.

Learn more about molecule here: brainly.com/question/26044300

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