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Semmy [17]
3 years ago
5

4 (x+2) as a word phrase

Mathematics
2 answers:
ycow [4]3 years ago
8 0
Four times the sum of x and two
bekas [8.4K]3 years ago
6 0
Well i think you should write this but you do not have to so here is my answer X+2times4 don't know if this works but than again im a beginner.
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What is the area of this square?
bogdanovich [222]

Answer:

6.25 mm squared

Step-by-step explanation:

Because if you multiply 2.5 by 2.5 you get 6.25. To find the area of a square you multiply the two sides its the same as a rectangle.

8 0
3 years ago
Help me please don’t need an explanation just a quick answer
Vikki [24]
Cfxgxhcgxjcbchcjchxjfhx
5 0
3 years ago
(ab^2 x -b^4a^3)^2<br><br> What is the answers
Umnica [9.8K]

Answer:

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

Step-by-step explanation:

Given the expression

\left(ab^2\:x\:-b^4a^3\right)^2

solving the expression

\left(ab^2\:x\:-b^4a^3\right)^2

\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2

a=ab^2x,\:\:b=b^4a^3

so the expression becomes

=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2

=a^2b^4x^2-2a^4b^6x+a^6b^8

Thus,

\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8

3 0
2 years ago
Multiple and simplify 4/7•35
allsm [11]

Answer:

20

Step-by-step explanation:

4/7 x 35 = 4 x 5

5 0
3 years ago
Read 2 more answers
The universal set in this diagram is the set of integers from 1 to 15. place the integers in the correct place in the venn diagr
neonofarm [45]

Answer:


Step-by-step explanation:

Given :  universal set in this diagram is the set of integers from 1 to 15.

Solution :

The intersection of odd integer,multiples of 3 and Factors of 15 are 3,15

The intersection of odd integer and Factors of 15 are 1,5

The intersection of odd integer,multiples of 3 is 9

The remaining multiples of 3 are 6,12

The remaining odd integers are 7,11,13

Now the remaining integers are 2,4,8,10,14 and these integers must be placed in the boxes outside the circles Since they does not belong any intersection or odd integer or factor of 15 .

Refer the attached figure for the answer.

3 0
2 years ago
Read 2 more answers
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