Sea turtle has the most momentum. I took the quiz and got that one right .
Answer:
3.53 m/s
Explanation:
KE₁ + RE₁ = KE₂ + RE₂ + PE
½ mv₁² + ½ Iω₁² = ½ mv₂² + ½ Iω₂² + mgh
For a solid sphere, I = ⅖ mr²
½ mv₁² + ½ (⅖ mr²) ω₁² = ½ mv₂² + ½ (⅖ mr²) ω₂² + mgh
½ mv₁² + ⅕ mr² ω₁² = ½ mv₂² + ⅕ mr² ω₂² + mgh
Rolling without slipping means v = ωr.
½ mv₁² + ⅕ mv₁² = ½ mv₂² + ⅕ mv₂² + mgh
⁷/₁₀ mv₁² = ⁷/₁₀ mv₂² + mgh
⁷/₁₀ v₁² = ⁷/₁₀ v₂² + gh
Substitute:
⁷/₁₀ (5.50 m/s)² = ⁷/₁₀ v₂² + (9.8 m/s²) (3.00 m sin 25.0°)
v₂ = 3.53 m/s
Hand pumps are manually operated pumps; they use human power and mechanical advantage to move fluids or air from one place to another. They are widely used in every country in the world for a variety of industrial, marine, irrigation and leisure activities. There are many different types of hand pump available, mainly operating on a piston, diaphragm or rotary vane principle with a check valve on the entry and exit ports to the chamber operating in opposing directions.
Hand pumps are manually operated pumps; they use human power and mechanical advantage to move fluids or air from one place to another. They are widely used in every country in the world for a variety of industrial, marine, irrigation and leisure activities. There are many different types of hand pump available, mainly operating on a piston, diaphragm or rotary vane principle with a check valve on the entry and exit ports to the chamber operating in opposing directions.
Answer:
English
Electrical phenomena are commonplace and unusual events that can be observed and that illuminate the principles of the physics of electricity and are explained by them. Electrical phenomena are a somewhat arbitrary division of electromagnetic phenomena
Los fenómenos eléctricos son eventos comunes e inusuales que se pueden observar y que iluminan los principios de la física de la electricidad y son explicados por ellos. Los fenómenos eléctricos son una división algo arbitraria de los fenómenos electromagnéticos.
Answer:
The value of Q is - 8 C
Explanation:
Given;
the magnitude of first charge = 2 C
position of the first charge = 0
_ (2m) 0(+2C) +(2m)(Q)
------------------------------------------------------------------------------------
E₁ --------------------------------->
<------------------------------------------------------------------ E₂
E₁ and E₂ are equal in magnitude but opposite in direction
| E₂ | = | E₁ |
Thus, since E₂ is opposite in direction to E₁, the Q = - 8 C
