Answer:
65.9°
Explanation:
When light goes through air to glass
angle of incidence, i = 35°
refractive index, n = 1.5
Let r be the angle of refraction
Use Snell's law
Sin r = 0.382
r = 22.5°
Now the ray is incident on the glass surface.
A = r + r'
Where, r' be the angle of incidence at other surface
r' = 60° - 22.5° = 37.5°
Now use Snell's law at other surface
Where, i' be the angle at which the light exit from other surface.
Sin i' = 0.913
i' = 65.9°
Answer:
The correct answer is V√5
Explanation:
Let V be the velocity of the satellite orbiting at radius r.
Let V(5r) be the velocity of the satellite orbiting at radius 5r.
Recall:
Escape velocity is given by:
V = √(2gr)
Where V is the escape velocity
g is the acceleration due to gravity
r is the radius of the earth.
With the above equation, we can obtain the answer to the question as follow:
V = √(2gr)
V(5r) = √(2g5r)
Next, we'll obtained the ratio of V(5r) to V as shown below
V(5r) : V => V(5r)/V
V(5r)/V = √(2g5r) / √(2gr)
V(5r)/V = √5
Cross multiply
V(5r) = V√5
From the above illustration, we can see that when the satellite is moved to 3r, then the expression for the velocity will be V√5
Answer:
The correct option is D
Explanation:
From the question we are told that
The refractive index of oil film is 
The thickness is 
Generally for constructive interference
![2t = [m + \frac{1}{2} ]* \frac{\lambda}{k}](https://tex.z-dn.net/?f=2t%20%20%3D%20%20%5Bm%20%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5D%2A%20%20%5Cfrac%7B%5Clambda%7D%7Bk%7D)
For reflection of a bright fringe m = 1
=> ![2 * (290*10^{-9}) = [1 + \frac{1}{2} ]* \frac{\lambda}{1.48}](https://tex.z-dn.net/?f=2%20%2A%20%28290%2A10%5E%7B-9%7D%29%20%20%3D%20%20%5B1%20%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%5D%2A%20%20%5Cfrac%7B%5Clambda%7D%7B1.48%7D)
=> 
This wavelength fall in the range of a yellow light
Answer:
energy carried by the current is given by the pointyng vector
Explanation:
The current is defined by
i = dQ / dt
this is the number of charges per unit area over time.
The movement of the charge carriers (electrons) is governed by the applied potential difference, when the filament has a movement the drag speed of these moving electrons should change slightly.
But the energy carried by the current is given by the pointyng vector of the electromagnetic wave
S = 1 / μ₀ EX B
It moves at the speed of light and its speed depends on the properties of the doctor and is not disturbed by small changes in speed, therefore the current in the circuit does not change due to this movement
