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storchak [24]
3 years ago
14

When you press your remote control you can see nothing coming from it. However, cameras on certain cell phones can photograph a

small circular beam. What is the best explanation for this?
Biology
2 answers:
e-lub [12.9K]3 years ago
6 0
The sensors in cameras are equipped to detect light frequencies that the human eye cannot.
SIZIF [17.4K]3 years ago
3 0

The answer is D (Remote controls often use infrared light to transmit information. This cannot be seen but can be picked up by some cameras.) I have had this question before.

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Nookie1986 [14]
The answer is 2. 2 Hydrogen atoms to 1 Oxygen atom.
8 0
3 years ago
What proves that eohippus is an ancestor of equus?
alisha [4.7K]

Answer:

It could be embreology. (I think i spelled that wrong)

Explanation:

It is a way to compare the embreos of two species to see the similarities between the two. If there are similarities then they have a common ancestor. If they don't have similarities then they arent from the same family.

4 0
4 years ago
Hey there... Can you help me please ?
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The first answer is A and the second answer is B
6 0
4 years ago
What is a food chain ???​
vazorg [7]

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5 0
3 years ago
Read 2 more answers
Cystic fibrosis is an autosomal recessive disorder. In one population, the frequency of affected individuals (A 2 A 2) is 0.0004
Simora [160]

Hardy Weinberg Equilibrium

Explanation:

  • Hardy Weinberg Equilibrium formula for allelic frequency is: p+q=1
  • Hardy Weinberg Equilibrium formula for genotypic frequency is: p^2+q^2+2pq=1
  • Here,p=frequency of dominant allele

                 q=frequency of recessive allele

                 p^2=frequency of dominant genotype

                 q^2=frequency of recessive genotype

                 2pq=frequency of heterozygous genotype

  • frequency of affected individuals=0.0004(given)

here,affected individuals means the one's having Cystic Fibrosis and since it is recessive disease so we can write frequency of recessive genotype as:     q^2=0.0004

  • If q^2=0.0004 q will be 0.02;frequency of recessive allele will be 0.02
  • Using the formula p+q=1

                                       p+0.02=1\\p=1-0.02=0.98

  • hence,frequency of dominant allele will be 0.98
  • Frequency of dominant genotype will be p^2=(0.98)^2=0.9604
  • Frequency of heterozygous genotype will be 2pq=2*0.98*0.02=0.0392

7 0
4 years ago
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