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Levart [38]
2 years ago
8

Find the ending balance if $500 was deposited at 5% annual interest compounded quarterly for 3 years.

Mathematics
1 answer:
leonid [27]2 years ago
3 0

Answer:

$575 ,

Step-by-step explanation:

5% of $500 is only $25

multiply that by 3YRS due to annual interest it would amount too

an addition $75 dollars so the answer is $575

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8 0
1 year ago
What is 0.75×2 please show your work need a answer today
attashe74 [19]
1.50 that should be it and i dont know how to show my work on a computer SORRY.
8 0
3 years ago
Read 2 more answers
find x. assume that segments that appear tangent are tangent. please help need answer and how to do it.
Pavlova-9 [17]
Triangle ABC is a right triangle, meaning we can use the Pythagorean Theorem to find x.
The formula for the Pythagorean Theorem is:
a =  \sqrt{ {b}^{2}  +  {c}^{2} }
where a is the hypotenuse, and b and c are the legs.
In this problem, we have the vertical leg as 16, the horizontal leg as x, and the hypotenuse as 20. Therefore, we can say that
a = 20 \\ b = 16 \\ c = x
Therefore, we can plug into the formula to find x:a =  \sqrt{ {b}^{2}  +  {x}^{2} }  \\  {a}^{2}  =  { \sqrt{ {b}^{2}  +  {x}^{2} } }^{2}  \\  {a}^{2}  =  {b}^{2}  +  {x}^{2}  \\  {a}^{2}  -  {b}^{2}  =  {x}^{2}
We first change the variable c to x and square both sides of the equation. Then we subtract b^2 from both sides.
{x}^{2}  =  {a}^{2}  -  {b}^{2}  \\  \sqrt{ {x}^{2} }  =  \sqrt{ {a}^{2}  -  {b}^{2} }  \\ x =  \sqrt{ {a}^{2} -  {b}^{2}  }
We square root each side to find the variable answer for x. Then we plug in the numbers:x =  \sqrt{ {(20)}^{2} -  {(16)}^{2}  }  \\ x =  \sqrt{400 - 256}  \\ x =  \sqrt{144}  \\ x = 12
We find that x = 12. The answer is A. 12.
3 0
3 years ago
The bulls-eye on a target has a diameter of 3 inches. The whole target has a diameter of 15 inches. What part of the whole targe
Helga [31]
Since a target is a circle and the bulls-eye is also a circle, the percent of the circle that is bulls-eye would be (Area of the bulls eye)/(Area of the target)

[tex] A = \pi r^{2} \\
d = 2r \\ r = \frac{d}{2} \\\\
\frac{ \pi ( \frac{d}{2})^{2}}{ \pi ( \frac{d}{2})^{2} }= \frac{ \pi ( \frac{3}{2})^{2}}{ \pi ( \frac{15}{2})^{2} }\\
\frac{ \pi ( \frac{3}{2})^{2} }{ \pi ( \frac{15}{2})^{2} } = \frac{ \pi (1.5)^{2} }{ \pi (7.5)^{2} } \\
\frac{ \pi (1.5)}{ \pi (7.5) } = \frac{ \pi (2.25)}{ \pi (56.25)}\\
\frac{ \pi (2.25)}{ \pi (56.25)}=\frac{2.25}{56.25}= 0.04 [tex]

So the bulls-eye takes up 4% of the target.
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3 years ago
Can someone please tell me what to do for this?? Thank you :))
bezimeni [28]

take it and leave it somewhere u will forget about it and move on with ur life lol

5 0
3 years ago
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