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3 years ago

3

Mathematics

2 answers:

kolezko [41]3 years ago

7 0

Answer:

left 2 units, up 3 units

Step-by-step explanation:

(x-2, y+3)

-2 means 2 to the left

+3 means 3 up

So it would be left 2 units, up 3 units.

inn [45]3 years ago

7 0

Answer:

<h3>left 2 units </h3><h3>up 3 units </h3><h3 />

Step-by-step explanation:

Rule:

If x+b right in b units

if x-b left in b untits

if y+b up in b units

if y-b down in b units

You don 't have to use this rule if you know that on the Ox axis the line goes horizontally (the abscissa axis); And on the Oy axis vertically (the ordinate axis)

Then :

x-2 left in 2 units

y+3 up in 3 units

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3 years ago

The coordinates of the vertices of triangle ABC are A(3,6), B(6, 3), and C(9, 9). If triangle ABC Is dilated by 1/3x and 1/3y to

katovenus [111]

Answer:

$A' = (1,2)$

$B'=(2,1)$

$C' =(3,3)$

Step-by-step explanation:

Given

$A = (3,6)$

$B = (6,3)$

$C = (9,9)$

$Scale = \frac{1}{3}$

Required

Determine the vertices of ABC

If truly the question asks for the vertices of ABC, then the vertices are:

$A = (3,6)$ $B = (6,3)$ $C = (9,9)$

However, I'm quite sure that's not the requirement of the question. So, I'll solve for A'B'C'

To do this, we simply multiply the vertices of ABC by the scale of dilation.

$(A'B'C') = Scale\ Factor * (ABC)$

$A' = \frac{1}{3} * A$

$A' = \frac{1}{3} * (3,6)$

$A' = (\frac{3}{3},\frac{6}{3})$

$A' = (1,2)$

$B' = \frac{1}{3} * B$

$B' = \frac{1}{3} * (6,3)$

$B' = (\frac{6}{3},\frac{3}{3})$

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$C' = (\frac{9}{3},\frac{9}{3})$

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spin [16.1K]

Answer:

The correct option is C.

Step-by-step explanation:

In a triangle, then sum of two smaller sides is greater than the length of third greatest side.

Let, in a triangle ABC, If the length of sides are $a$ , then

$c$

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In option D,

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