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2 years ago

9

PLEASE HELP ME ASAP

1 answer:

Valentin [98]2 years ago

7 0

Wow this is CONFUSING

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2 years ago

If log2 5 = k, determine an expression for log32 5 in terms of k.

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Answer:

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Step-by-step explanation:

Let's start by using change of base property:

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So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

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Using reduction of power property:

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Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

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$\frac{log(5)}{log(2)} =k\\$

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3 years ago

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Step-by-step explanation:

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