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Aleksandr-060686 [28]
3 years ago
11

Please helpp and show your work pleasee

Mathematics
1 answer:
spin [16.1K]3 years ago
3 0

Answer:

b=27

Step-by-step explanation:

\frac{b}{3} -7=2\\\\\frac{b}{3}=9\\\\b=27

<u>Invisible Steps:</u>

Add 7 on each side of the equation:

\frac{b}{3}-7+7=\frac{b}{3}\\2+7=9

Multiple 3 on each side of the equation:

\frac{b}{3} · 3=b

9 · 3=27

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The mean annual tuition and fees for a sample of 14 private colleges in California was $37,900 with a standard deviation of $7,2
JulijaS [17]

Answer:

Z_{0.005}>Z H₀ is wrong and other is correct. IT means $35000 is not mean value.

Step-by-step explanation:

Two hypothesis:

H₀=$35,000

Hₐ≠$35,000

Test Formula:

Z=\frac{(X-u)}{\frac{S}{\sqrt{n} } }

Where:

X is the mean value=$37,900

u is the value with 0.01 significance=$35000

S is the standard deviation

n is the sample size

Z=\frac{(37900-35000)}{\frac{7200}{\sqrt{14} } }

Z=1.507

Z with 0.01 significance:

0.01/2=0.005=0.05%

Degrees of freedom=14-1=13

From t distribution table at 0.05% and 13 dof:

Z_{0.005}=4.221

So

Z_{0.005}>Z H₀ is wrong and other is correct. IT means $35000 is not mean value.

7 0
4 years ago
Y=Cosx.arcsinx<br> What is the solution
Alinara [238K]

Step-by-step explanation:

Given: y = cos(sin^{-1}x))

As the domain for the inverse sine function is 1  ≤  x  ≤  1  as this is the range for the sine function.

The range for the function is the same as the range for the cosine function, 1  ≤  y  ≤  1

As

sin^{2}x +cos^{2}x = 1

So, using the identity cos(x) = \pm \sqrt{1-sin^{2}(x) }

y = \pm \sqrt{1-sin^{2}(sin^{-1}(x)) }

As the sin and inverse sin function do cancel each other, so only x² is left.

Hence,

y = \pm \sqrt{1-x^{2} ; -1\leq x\leq 1

<em>Keywords: trigonometric function </em>

<em>Learn more trigonometric function from brainly.com/question/12551115</em>

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Answer:360

Step-by-step explanation:

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3 years ago
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1 because if you were to get h rn e measure of the problem right here it would be a cosine of 1
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