In order to accurately answer any fraction, it is best to have a common denominator (bottom of the fraction)
Since in
, 100 is the denominator, you need to make the other fraction with the same denominator
So Multiply
by <u />
So
or
You can do this another way which involves the opposite way of multiplying which is by dividing
Since you have to get a common denominator to measure accurately no matter what, you can divide
One thing to know is that when dividing fractions, both the denominator and numerator have to be divided by a factor to be divided and result in a whole number
÷
=
So just have to multiple
⇒
⇒
The results are the same
Again
is greater than
Answer:
18x² - 6x
Step-by-step explanation:
Differentiate using the product rule, that is
y = f(x)g(x), then
= f(x)g'(x) + g(x)f'(x)
here
f(x) = 3x² ⇒ f'(x) = 6x
g(x) = 2x - 1 ⇒ g'(x) = 2, thus
(3x²(2x - 1)
= 3x² × 2 + 6x(2x - 1)
= 6x² + 12x² - 6x
= 18x² - 6x
Answer:
QR = 13.3
Step-by-step explanation:
We solve using Pythagoras Theorem
c² = a² + b²
RP² = PQ² + QR²
QR² = RP² - PQ²
QR = √RP² - PQ²
RP=15
PQ=7
QR = √15² - 7²
QR = √(176)
QR = 13.266499161
Approximately = 13.3
Therefore, the length of QR = 13.3
Answer:
10
Step-by-step explanation:
10+20=30
20 is two times 10
Since Thomas's age is half, Thomas's age is 10
The scuba diver's position relative to sea level after the 4.6 minutes is 5.1 ft.
Given:
A scuba diver descends in the water at a rate of 23 1/2 feet per minute for 2.6 minutes.
A scuba diver ascends at a rate of 28 feet per minute for 2 minutes after seeing a big fish.
To find :
The scuba diver's position relative to sea level after the 4.6 minutes.
Solution:
Rate of a scuba diver descending in the water for 2.6 minutes =
Distance covered by a scuba diver in 2.6 minutes =
Rate of a scuba diver ascending for 2 minutes =
Distance covered by a scuba diver in 2 minutes =
The position of scuba diver after 4.6 minutes relative to sea level:
The scuba diver's position relative to sea level after the 4.6 minutes is 5.1ft.
Learn more about ascending rate and descending rate here:
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