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3 years ago

What are saturated and non saturated vapour?

Physics

1 answer:

Elodia [21]3 years ago

8 0

Answer:

A saturated vapour is one that is in balance with its own liquid. Space is considered to be unsaturated if it contains fewer vapours than the maximum amount it can retain at a given temperature. Saturated vapour pressure is unaffected by volume, although it rises as temperature rises.

Explanation:

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If the speed of a wave is 2.5 x 103 m/s and has a wavelength of 5.80 x 10-7m, what is its frequency?

trasher [3.6K]

Answer:

4.31×10⁹Hz

Explanation:

v=2.5×10³ms⁻¹ wavelength=5.80×10⁻⁷m

v=frequency × wavelength

2.5×10³=f×5.80×10⁻⁷

f=4.31×10⁹Hz

8 0

4 years ago

A block with mass m = 0.450 kg is attached to one end of an ideal spring and moves on a horizontal frictionless surface. The oth

svetoff [14.1K]

Answer:

k = 26.25 N/m

Explanation:

given,

mass of the block= 0.450

distance of the block = + 0.240

acceleration = a_x = -14.0 m/s²

velocity = v_x = + 4 m/s

spring force constant (k) = ?

we know,

x = A cos (ωt - ∅).....(1)

v = - ω A cos (ωt - ∅)....(2)

a = ω²A cos (ωt - ∅).........(3)

$\omega = \sqrt{\dfrac{k}{m}}$

now from equation (3)

$a_x = \dfrac{k}{m}x$

$k = \dfrac{m a_x}{x}$

$k = \dfrac{0.45 \times (-14)}{0.24}$

k = 26.25 N/m

hence, spring force constant is equal to k = 26.25 N/m

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4 years ago

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Two bumper cars move toward each other. the cars hit and bounce off of each other. the momentum before the collision will be equ

anygoal [31]

The answer is the MOMENTUM before the collision is equal to the MOMENTUM after.

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3 years ago

Read 2 more answers

An electron moves along the z-axis with vz=4.1Ã107m/s. As it passes the origin, what are the strength and direction of the magne

Artist 52 [7]

Answer:

The value of magnetic field is $B_a=6.56*10^{-19} T$

In the direction of the positive x - axis

The value of magnetic field is $B_a=6.56*10^{-19} T$

In the direction of the positive z - axis

Explanation:

From the question we are told that

The velocity of the electron is $v_z = 4.1*10^{7}m/s$

Considering the first position

The equation for the magnetic field is

$\= B = \frac{\mu_0}{ 4 \pi} \frac{q \=v * \= r}{r^2}$

Now $r = \sqrt{i^2 + j^2 + k^2}$

substituting values

$r = \sqrt{1^2 +0^2 +0^2}$

$= 1$

$\= r = \frac{\r r}{r}$

$\r r = 1 i + 0j + 0k$

Therefore $\= r = \frac{1i + 0j + 0k}{1}$

$= i$

So Substituting $4 \pi *10^ {-7}$ for $\mu_o$ , $1.602 *10^{-19}$ for q

$\= B_a = \frac{4\pi *10^{-7}}{4 \pi} \frac{1.602 *10^{-19} * 4.1*10^{7} * i}{1^2}$

$\= B_a=6.56*10^{-19} T (i)$

Considering the second position

Here

$r = \sqrt{0^2 + 0^2 + 2^2}$

$=2$

$\= r = \frac{\r r}{r}$

$\r r = 0 i + 0j + 2k$

$\= r = \frac{0i + 0j + 2k}{2}$

$= k$

So Substituting $4 \pi *10^ {-7}$ for $\mu_o$ , $1.602 *10^{-19}$ for q

$\= B_a = \frac{4\pi *10^{-7}}{4 \pi} \frac{1.602 *10^{-19} * 4.1*10^{7} * k}{1^2}$

$\= B_a=6.56*10^{-19} T (k)$

6 0

4 years ago

I need help on this question.

stira [4]

Answer:

<em>Answer: B. 49 N</em>

Explanation:

<u>Friction Force </u>

When an object is at rest on a rough surface, it encounters a friction force that opposes motion.

The friction force when an object is moving on a horizontal surface is calculated by:

$Fr=\mu_k N$

Where $\mu_k$ is the coefficient of static friction and N is the normal force.

If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:

N = W = m.g

Thus, the friction force is:

$Fr=\mu_k W$

We are given the coefficient of static friction $\mu_k=0.5$ and the mass of the object m=10 Kg. The minimum force needed to make it start moving is the maximum friction force:

Fr=0.5*10*9.8

Fr = 49 N

Answer: B. 49 N

8 0

3 years ago

What are saturated and non saturated vapour? ​

What are saturated and non saturated vapour?