Question

A javelin is thrown at 28.5 m/s from flat

Answer 1

The time for the javelin in the air will be 3.977 second

What is the period?

The value of time needed to complete the upward and the downward motion is the total period. Its unit is the second and is denoted by t. T is the time at which the ball first hits the ground.

Given data;

Θ is the angle of throw = 43.2°

u is the thrown velocity =  28.5 m/s

t is the  time for the javelin in the air

The time period is found as;

$\rm t = \frac{2u sin \theta }{g} \\\\ t = \frac{ 2 \times 28.5 \ sin 430.2^0}{9.81 } \\\\ t = 3.977 \ sec.$

Hence the time for the javelin in the air will be 3.977 second

To learn more about the period, refer to the link;

brainly.com/question/569003

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Answer 2

Answer:

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Explanation: