A javelin is thrown at 28.5 m/s from flat
2 answers:
The time for the javelin in the air will be 3.977 second
<h3>What is the period?</h3>The value of time needed to complete the upward and the downward motion is the total period. Its unit is the second and is denoted by t. T is the time at which the ball first hits the ground.
Given data;
Θ is the angle of throw = 43.2°
u is the thrown velocity = 28.5 m/s
t is the time for the javelin in the air
The time period is found as;
Hence the time for the javelin in the air will be 3.977 second
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Answer:
9.82 × Hz
Explanation:
De Broglie equation is used to determine the wavelength of a particle (e.g electron) in motion. It is given as:
λ =
where: λ is the required wavelength of the moving electron, h is the Planck's constant, m is the mass of the particle, v is its speed.
Given that: h = 6.63 × Js, m = 2.50 kg, v = 2.70 m/s, the wavelength, λ, can be determined as follows;
λ =
=
=
= 9.8222 ×
The wavelength of the object is 9.82 × Hz.