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iren2701 [21]
2 years ago
11

A javelin is thrown at 28.5 m/s from flat

Physics
2 answers:
zavuch27 [327]2 years ago
4 0

The time for the javelin in the air will be 3.977 second

<h3>What is the period?</h3>

The value of time needed to complete the upward and the downward motion is the total period. Its unit is the second and is denoted by t. T is the time at which the ball first hits the ground.

Given data;

Θ is the angle of throw = 43.2°

u is the thrown velocity =  28.5 m/s

t is the  time for the javelin in the air

The time period is found as;

\rm  t = \frac{2u sin \theta }{g} \\\\ t = \frac{ 2 \times 28.5   \ sin 430.2^0}{9.81 } \\\\ t = 3.977  \ sec.

Hence the time for the javelin in the air will be 3.977 second

To learn more about the period, refer to the link;

brainly.com/question/569003

#SPJ2

dolphi86 [110]2 years ago
4 0

Answer:

did you ever the answer?

Explanation:

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