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3 years ago

Solve the equation. Enter your answer in the box. V27

Mathematics

2 answers:

Lilit [14]3 years ago

5 0

3

step by step explanation: when it has the little 3, it means what number would need to be divided by itself to equal the number

hope this helps

faust18 [17]3 years ago

4 0

The correct answer is 3

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3) A box of tile contains 12 tiles. If

vichka [17]

Answer:

3 tiles left

Step-by-step explanation:

You can only use a maximum of 9 tiles to make a perfect square. You would need 7 more tiles to make a larger square. Having used 9 tiles, you will have 3 leftover. (12 - 9 = 3)

Hope I helped!

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3 years ago

What is 171 plus 727 using rounding for the estimated sum

Alchen [17]

898 rounded answer is 900

8 0

3 years ago

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You want to apply a weed killer to your lawn. The directions on the bottle call for mixing 3 ounces of weed killer with 2 gallon

Alborosie

5/2 = 2.5

3 ounces x 2.5 = 7.5 ounces of weed killer

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3 years ago

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3 years ago

In order to evaluate 7 sec(θ) dθ, multiply the integrand by sec(θ) + tan(θ) sec(θ) + tan(θ) . 7 sec(θ) dθ = 7 sec(θ) sec(θ) + ta

Maurinko [17]

Answer:

$\int {7 \sec(\theta) } \, d\theta = 7\ln(\sec(\theta) + \tan(\theta)) + c$

Step-by-step explanation:

The question is not properly formatted. However, the integral of $\int {7 \sec(\theta) } \, d\theta$ is as follows:

$\int {7 \sec(\theta) } \, d\theta$

Remove constant 7 out of the integrand

$\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) } \, d\theta$

Multiply by 1

$\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) * 1} \, d\theta$

Express 1 as: $\frac{\sec(\theta) + \tan(\theta) }{\sec(\theta) + \tan(\theta)}$

$\int {7 \sec(\theta) } \, d\theta = 7\int {\sec(\theta) * \frac{\sec(\theta) + \tan(\theta) }{\sec(\theta) + \tan(\theta)}} \, d\theta$

Expand

$\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{\sec^2(\theta) + \sec(\theta)\tan(\theta) }{\sec(\theta) + \tan(\theta)}} \, d\theta$

Let

$u = \sec(\theta) + \tan(\theta)$

Differentiate

$\frac{du}{d\theta} = \sec(\theta)\tan(\theta) + sec^2(\theta)$

Make $d\theta$ the subject

$d\theta = \frac{du}{\sec(\theta)\tan(\theta) + sec^2(\theta)}$

So, we have:

$\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{\sec^2(\theta) + \sec(\theta)\tan(\theta) }{u}} \,* \frac{du}{\sec(\theta)\tan(\theta) + sec^2(\theta)}$

Cancel out $\sec(\theta)\tan(\theta) + sec^2(\theta)$

$\int {7 \sec(\theta) } \, d\theta = 7\int {\frac{1}{u}} \,du}}$

Integrate

$\int {7 \sec(\theta) } \, d\theta = 7\ln(u) + c$

Recall that: $u = \sec(\theta) + \tan(\theta)$

$\int {7 \sec(\theta) } \, d\theta = 7\ln(\sec(\theta) + \tan(\theta)) + c$

8 0

3 years ago

Solve the equation. Enter your answer in the box. V27​

Solve the equation. Enter your answer in the box. V27