Answer:
Step-by-step explanation:
Solve the equation. Enter your answer in the box. V27
2 answers:
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Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.
Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.
Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.
Answer: The coordinate of the solution is (0.25,-0.5)
Step-by-step explanation:
the solution is (0.25,-0.5) because when you graph them on a graph, they both intercept at that point.
