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3 years ago

Geomtry plz help 15 points

Mathematics

2 answers:

Anton [14]3 years ago

7 0

Answer:

$DE=5x-12$

Step-by-step explanation:

From this we can see this is an equilateral triangle

So, both sides to make every angle equal have to be the same

That's why $DE=5x-12$

Brainliest please

gulaghasi [49]3 years ago

4 0

Answer:

DE = 5x-12 (base angles of isos triangle)

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Flauer [41]

The path of the ball is an illustration of absolute equation.

The equation of the path is: $y =- \frac{12}7|x- 4.8| + 6.4$

The given parameters are:

$(h,k) = (4.8,6.4)$ --- the vertex (i.e. the point where the ball hits the wall)

$(x_1,y_1) = (2,1.6)$

$(x_2,y_2) = (7.6,1.6)$

An absolute function is represented as:

$y = a |x - h| + k$

Substitute $(h,k) = (4.8,6.4)$

$y = a |x - 4.8| + 6.4$

Substitute $(x_1,y_1) = (2,1.6)$ for x and y

$1.6 = a|2 - 4.8| + 6.4$

$1.6 = a|- 2.8| + 6.4$

Remove absolute bracket

$1.6 = 2.8a + 6.4$

Collect like terms

$2.8a = -6.4+1.6$

$2.8a =- 4.8$

Solve for a

$a =-\frac{4.8}{2.8}$

Simplify

$a =-\frac{12}{7}$

Substitute $a =-\frac{12}{7}$ in $y = a |x - 4.8| + 6.4$

$y =- \frac{12}7|x- 4.8| + 6.4$

Hence, the equation of the path is: $y =- \frac{12}7|x- 4.8| + 6.4$

See attachment for graph that models the path

Read more about absolute equations at:

brainly.com/question/2166748

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Which of the following equations would not have a solution that is the same as the solution to the system. shown below?

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What are two answers for 2 / 3 - 5 / 12

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Answer:

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Step-by-step explanation:

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Read 2 more answers

The true average diameter of ball bearings of a certain type is supposed to be 0.05 in. A one-sample t-test will be carried out

satela [25.4K]

Answer:

a) H0: $\mu \leq \mu_o$

H1: $\mu > \mu_o$

n = 13 represent the sample size

$t = 1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12} >1.6) = 0.068$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

b) H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 13 represent the sample size

$t = -1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12}$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

c) H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 25 represent the sample size

$t = -2.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 25-1=24$

We can calculathe the p value with this formula:

$p_v = P(t_{24}$

Since $p_v$ we can reject the null hypothesis on this case at 1% of significance.

Step-by-step explanation:

Part a

For this case we assume that we are testing the following system of hypothesis

H0: $\mu \leq \mu_o$

H1: $\mu > \mu_o$

n = 13 represent the sample size

$t = 1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12} >1.6) = 0.068$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

Part b

For this case we assume that we are testing the following system of hypothesis

H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 13 represent the sample size

$t = -1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12}$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

Part c

For this case we assume that we are testing the following system of hypothesis

H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 25 represent the sample size

$t = -2.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 25-1=24$

We can calculathe the p value with this formula:

$p_v = P(t_{24}$

Since $p_v$ we can reject the null hypothesis on this case at 1% of significance.

8 0

3 years ago