The question is incomplete, here is the complete question:
The rate of certain reaction is given by the following rate law:
![rate=k[H_2]^2[I_2]^2](https://tex.z-dn.net/?f=rate%3Dk%5BH_2%5D%5E2%5BI_2%5D%5E2)
At a certain concentration of
and
, the initial rate of reaction is 4.0 × 10⁴ M/s. What would the initial rate of the reaction be if the concentration of
Answer : The initial rate of the reaction will be,
Explanation :
Rate law expression for the reaction:
![rate=k[H_2]^2[I_2]^2](https://tex.z-dn.net/?f=rate%3Dk%5BH_2%5D%5E2%5BI_2%5D%5E2)
As we are given that:
Initial rate = 4.0 × 10⁴ M/s
Expression for rate law for first observation:
....(1)
Expression for rate law for second observation:
....(2)
Dividing 2 by 1, we get:
![\frac{R}{4.0\times 10^4}=\frac{k(\frac{[H_2]}{2})^2[I_2]^2}{k[H_2]^2[I_2]^2}](https://tex.z-dn.net/?f=%5Cfrac%7BR%7D%7B4.0%5Ctimes%2010%5E4%7D%3D%5Cfrac%7Bk%28%5Cfrac%7B%5BH_2%5D%7D%7B2%7D%29%5E2%5BI_2%5D%5E2%7D%7Bk%5BH_2%5D%5E2%5BI_2%5D%5E2%7D)


Therefore, the initial rate of the reaction will be, 
Answer:
D. All of them would have the same kinetic energy
Explanation:
The expression for the kinetic energy of the gas is:-
k is Boltzmann's constant =
T is the temperature
<u>Since, kinetic energy depends only on the temperature. Thus, at same temperature, at 300 K, all the gases which are
will posses same value of kinetic energy.</u>
Answer:
When two people "collide" and one of them is carrying the virus then the other person starts carrying it. This is why we need to social distance so it doesn't spread.
Explanation:
Answer:
and
are ionization isomers.
and
are linkage isomers.
Explanation:
Ionization isomerism occur when a ligand that is bound to the metal center exchanges places with an anion or neutral molecule that was originally outside the coordination complex
Thus
and
are ionization isomers.
Linkage isomerism is the existence of coordination compounds that have the same composition differing with the connectivity of the metal to a ligand.
Thus
and
are linkage isomers.
MgCO3 will remain undissolved and
NaNO3 will dissolve