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Considering the reaction stoichiometry, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.
<h3 /><h3>Reaction stoichiometry</h3>The balanced reaction is:
3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Cu: 3 moles
- HNO₃: 8 moles
- Cu(NO₃)₂: 3 moles
- NO: 2 moles
- H₂O: 4 moles
It is possible to determine the the amount of moles of NO produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 2 moles of NO, if 27 moles of HNO₃ react how many moles of NO will be formed?
<u><em>amount of moles of NO= 6.75 moles</em></u>
In summary, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.
Learn more about reaction stoichiometry:
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Answer: 7.8 moles of NaCl result from the complete reaction of 3.9 mol of
Explanation:
To calculate the moles :
As is the excess reagent,
is the limiting reagent as it limits the formation of product.
According to stoichiometry :
1 mole of gives = 2 moles of
Thus 3.9 moles of will give=
of
7.8 moles of NaCl result from the complete reaction of 3.9 mol of