If f(x)=x^2+1 and g(x)=3x+1 find 2*f(4)

If 6/10 is multiplied by a fraction less than 1,which of these would be an answer 6/10,1/2,3/2,or 5

Pavlova-9 [17]

If $\frac{6}{10}$ is multiplied with a fraction less than 1, out of the given options $\frac{1}{2}$ would be the answer.

Explanation:

First, we need to determine what a fraction lesser than 1 is. If the numerator is lesser than the denominator, the fraction will be lesser than 1 whereas if the denominator is higher than the numerator is would equal more than 1.
If $\frac{6}{10}$ is multiplied with 1, we get the value $\frac{6}{10}$ . Since the fraction must be lesser than 1, $\frac{6}{10}$ cannot be an answer. So option 1 cannot be the answer.
The value of $\frac{6}{10}$ is 0.6. If it is multiplied with any value lesser than 1, the resulting value cannot be higher than the value of 0.6. The value of the fraction $\frac{3}{2}$ is 1.5 and the value of 5 are both greater than 0.6. So the third and fourth options cannot be the answer. So $\frac{1}{2}$ is the answer.

4 0

3 years ago

Reduce any fractions to lowest terms. Don’t round your answer , and don’t use mixed fractions.

kati45 [8]

Answer:

x ≥ -1

Step-by-step explanation:

Hope this helps

7 0

3 years ago

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0

3 years ago

What the word form 485,830

Anastasy [175]

the word form of 485,830 is Four hundred eighty-five thousand eighty hundred thirty

7 0

3 years ago

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For which data set is a linear regression most reasonable?

Oxana [17]

Answer:

The correct option is;

A. A set of nine data pairs with a correlation coefficient r = -0.4

Step-by-step explanation:

In statistical analysis, it is important to make use of an adequate sample size in order to arrive at a valid result. An analysis with a very small sample size can provide misleading results

When performing regression analysis it is generally accepted by researchers that each variable should have at least 10 observations.

Therefore, the data set having nine data pairs with a negative correlation of -0.4 will provide the most valid result that can then be used for generalization about the larger statistical population.

6 0

3 years ago

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